Quote Originally Posted by Maven View Post
One thing you will have problems with is common multiples.

2*5 = 10 and 2*5*3 = 30

So every so many hops your double counting.
Pretty sure you added that to your post after Olaf's reply in #30 (i.e. in your edit of 30/6/14 @ 12:14am) - back-dating your posts is hardly playing fair!

I'd quite like to see your solution to the problem, too, out of interest. Saying it is simple and pointing the reader to Google in a thread you began in order to educate people is a little strange, IMO. Eliminating the intersections of common multiples is most certainly not 'straight-forward'.