Well, that' s just not how you solve those types of equations. Maybe I misunderstood. Are you trying to choose the pressure and angle given a certain distance you want the water stream to go?

Anyway, if you want to compute the angle, x, made between the nozzle and the horizontal if you're given the distance and initial launch speed you'll need to convert the equation I gave before.

Use the following trig relationship to help you out:

sin(x) cos(x) = 1/2 * sin(2x)

Now you can solve directly for x.


x = 1/2 * arcsin(g*d/V^2)