I hate it so much!

[vbzero]

If anyone is able to do that, please reply:

1. Create a new form in your project and set it as the
startup form.

2. Add a second form that can be used as dialog.

3. Add a button to the dialog form and then do the following:

When the application starts, the startup form should
call the dialog form to be shown on the screen.
During this, the startup form has to be disabled for a while.

The second form has a button and if you click it, it should
enable the first form and close the dialog.

Can anybody do that in C# or VB.NET?

thx!

[Scott Penner]

Make the two forms with VS.net. Create the dialog form in the constructor of the main form, before InitializeComponent is called, and show it with the ShowDialog method. When your dialog is done, just call the close method on it, and the program will continue as usual. If you need feedback from the dialog, you will have to create a public property that the main form can read once the dialog is closed.

// Constructor of primary form (startup)
public MainForm()
{
   // Create the dialog and show it.
   TestDialog MyDialog = new TestDialog();
   MyDialog.ShowDialog();

   //
   // Required for Windows Form Designer support
   //
   InitializeComponent();
    
} 

[vbzero]

Not at all...

I need to disable the Main form and
when the dialog closes, the Main form
should be enabled again.

'MainForm.Enabled = False' ?

[DevGrp]

Try this

this.Hide();

[vbzero]

this only works for the current form - not for another form

[vbzero]

I can't understand why this is so a big problem - in VB 6
this was always possible - what the hell have they done?

[donut]

i have a similar problem, in that i have a form that loads another form, but if i try to unload the first form from the second form, it unloads the entire project!

[vbzero]

How do you try to unload the first form?

(in code)

[donut]

well, actually i just had a brief memory lapse, that wasn't quite what i meant. if i try to load the second form, and then unload the first form, it unloads the project, like this:

Form2 frm = new Form2
frm.Show
this.Dispose(True)

but that is a good question, how would you unload a form from another form...

[Serge]

If I understand you correctly, you want to show form2 as modal form:

private void Form1_Load(object sender, System.EventArgs e)
{
    this.Show();
    this.Activate();
    Form2 frm = new Form2();
    //notice [b]this[/b] object is being passed to the ShowDialog method. This parameter defines the owner
    //this will make the Form2 as modal
    frm.ShowDialog(this);
} 

[Scott Penner]

I'm not sure what the big deal is. Maybe we're not understanding the problem...

You should be able to do this in several ways. You can either use the ShowDialog like Serge and I suggested, which automatically disables the first form (easiest way).

Or, you can declare the second form as a private variable in the class. Then, show it non-modally (.Show) and hide the current form after it is shown (This.Hide). In order to show the main form after the dialog is closed, simply respond to the dialog form's Closed event.

If this doesn't solve the problem, can you better explain it for us?