**SOLVED coefficents of resistance

[oddprime]

I have used the stienhar-hart
1/T = a + b(LN R) + c(Ln R)^3

to get my coefficents
0.000484976
0.000311308
0.000000490

Now with this information how do I determine
what the temperature is ?


Brad

The answer is simply plugging in the numbers where 5875 is the resistance of the range 0 to 65535

1 / 0.000484976 + 0.000311308 * LN(5875) + 0.000000490 *
(LN(5875)^3) - 273.15 == 12C

Brad

[oddprime]

I guess I should of added the range :-)
0 to 65535

and a brief explamation.
I have hooked up (2) 10k ohm thermistors
to the joystick port since it is an analog to
digital converter with a range of 0 to 65535
I can see the resistance being done by
the thermistors with the X and Y position of a
standard joystick driver. I have an application
already that after I put in the coefficients will
determine the temperature. My question is
how it does it... I have the coeficcients as listed
above I just dont know how it takes coefficeients
and the range 0 to 65535 and determines the temperature.

thanks for any help
Brad

[wy125]

Are you asking for an explanation of the relationship between the resistance of a thermistor and its temperature?