Please solve

[prog_tom]

I have a question, can anyone solve this equation step by step and explain?

I/{sqrt[(x-10)^2+(y-0)^2]}^2=2I/{sqrt[(x-20)^2+(y-0)^2]}^2

If you want you can turn to page 578 on Algebra 2 book, it mentioned there, I do not understand how after simplify, it can form x^2+y^2=200

Thanks

[JungleMan]

Originally posted by prog_tom
If you want you can turn to page 578 on Algebra 2 book

And I'm supposed to have your algebra book?

[Gimlin]

Originally posted by jpbtennisman


And I'm supposed to have your algebra book?

[clears throat] I beilive you are supposed to have algebra 2

[JungleMan]

Originally posted by Gimlin


[clears throat] I beilive you are supposed to have algebra 2

haha, nice call

but still...

[thinktank2]

Originally posted by prog_tom
I have a question, can anyone solve this equation step by step and explain?

I/{sqrt[(x-10)^2+(y-0)^2]}^2=2I/{sqrt[(x-20)^2+(y-0)^2]}^2

If you want you can turn to page 578 on Algebra 2 book, it mentioned there, I do not understand how after simplify, it can form x^2+y^2=200

Thanks

I/{sqrt[(x-10)^2+(y-0)^2]}^2=2I/{sqrt[(x-20)^2+(y-0)^2]}^2

is the same as

I/[(x-10)^2+(y-0)^2] = 2I/[(x-20)^2+(y-0)^2]

or

I/[(x-10)^2+ y^2] = 2I/[(x-20)^2+ y^2]


Dividing both sides by I

1/[(x-10)^2+ y^2] = 2/[(x-20)^2+ y^2]


Cross multiplying both sides,

[(x-20)^2+ y^2] = 2 * [(x-10)^2+ y^2]

or

2 * [(x-10)^2+ y^2] = [(x-20)^2+ y^2]

Expanding powers

2 (x^2 + 100 - 20x + y^2) = x^2 + 400 - 40x + y^2

2x^2 + 200 - 40x + 2y^2 = x^2 + 400 - 40x + y^2

Moving the Right side terms to the Left

2x^2 + 200 - 40x + 2y^2 - (x^2 + 400 - 40x + y^2) = 0

2x^2 + 200 - 40x + 2y^2 - x^2 - 400 + 40x - y^2 = 0

2x^2 - x^2 + 200 - 400 - 40x + 40x + 2y^2 - y^2 = 0

x^2 - 200 + y^2 = 0

Taking the 200 to the RHS

x^2 + y^2 = 200

[prog_tom]

thanks, another question:

Please write sqrt(27) in terms of i

[NotLKH]

Originally posted by prog_tom
thanks, another question:

Please write sqrt(27) in terms of i

That was Fun!

[prog_tom]

Youare that Moore dude?

[NotLKH]

Originally posted by prog_tom
Youare that Moore dude?

Sorry, No. I'm just your friendly, neighborly Spider-Ma...oops!
Been reading the SpiderMan Book Adaptation, just kinda slipped out.
Actually, I'm not sure who you mean?

Anyways, like my Square root of 27 using i?

[riis]

Please write sqrt(27) in terms of i

What is i?

Do you mean that, if i = 3, sqrt(27) = i * sqrt(i)?

[prog_tom]

I guess in this case the i is referring to the complex numbers.