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Jan 31st, 2002, 08:57 AM
#1
Thread Starter
Hyperactive Member
Integral
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Integrate (e^(x^2))dx
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Feb 2nd, 2002, 07:45 PM
#2
New Member
There was a question a while ago on the Dr. Math Forum, it might be usefull:
http://mathforum.org/dr.math/problems/jaw6.1.96.html
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Feb 2nd, 2002, 07:48 PM
#3
New Member
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Feb 6th, 2002, 02:52 PM
#4
Member
your talking about a popular integral from statistics. You need to switch coordinate systems to evaluate it. Think college calculus level 3
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Feb 6th, 2002, 04:17 PM
#5
Fanatic Member
Info.
I just fed the integral into the 'Integrator' at http://integrals.wolfram.com/
It spat the following out... 
Information on the Erfi function can be found here... http://mathworld.wolfram.com/Erfi.html
Hope this helps.
Digital-X-Treme
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[VBCODE]Debug.Print Round(((1097) - ((55 ^ 5 + 311 ^ 3 - 11 ^ 3) _
/ (68 ^ 5))) ^ (1 / 7), 13)[/VBCODE]
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Feb 6th, 2002, 04:32 PM
#6
New Member
the integral of e^f(x) is f'(x)e^f(x), therefore e^(x^2) = 2xe^(x^2).
make any sense?
e^function = derivated of function x e^function
*I tried my best and falied miserably, the lesson... Never try.* - Homer J
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Feb 7th, 2002, 05:54 PM
#7
Hyperactive Member
Originally posted by vbPhr33k
the integral of e^f(x) is f'(x)e^f(x), therefore e^(x^2) = 2xe^(x^2).
make any sense?
e^function = derivated of function x e^function
dude, what you have done is called differentiation.
for example:
Differentiation [e^(ax)] = a.e^(ax) .dx
Integral [e^(ax) .dx] = [(e^(ax))/a] + c
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