A cicular target with radius of 12 inches is to have a
cicular bull's-eye painkted in teh center,
so that the area of bull's eye is 1% of the total area of the target.
What should the radius of the bull's-eye be in inches?

A. 0.12 B. 1.2 C. 1/sqr(pie) D. 12/sqr(145) E. 0.0

the bulls eye should be 1.2 ".

A = pi(r)^2
A = pi(12)^2
A = 452.3 the area of the target

452.3 * 0.01 = 4.524 the area of the bulls eye

A = pi(r)^2
4.524 = pi(r)^2

divide this by pi

4.524 / pi = r^2

then square root it

sqrt(4.524 / pi) = r

so r finally works out to 1.2