Simple question(extremely)

[DiGiTaIErRoR]

I'm converting c++ code to VB and I'm a newbie so....

how would I put this in VB terms?

byte b = (byte)inStr.charAt(i);

instr is a string, i'm guessing charat does a mid$(string,i,1)

Help!

Thanks,

[filburt1]

That looks like Java to me but:

Dim b As String * 1
b = Mid$(inStr, i, 1)

[DiGiTaIErRoR]

I need b as a byte.

So would I Asc it?

Also ^ does power in c++ right?

[filburt1]

There is no power operator in C++, you've got to make your own or use stuff from math.h.

A byte is a value from 0 to 255 when unsigned so my string declaration should be right.

[DiGiTaIErRoR]

Filburt, check your private messages I sent you something, please help me.

Thanks

[jim mcnamara]

^ is the xor operator.