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Nov 21st, 1999, 10:30 AM
#1
Thread Starter
Junior Member
I need a For Next loop that will print the first 10 Fibonacci numbers 1,1,2,3,5,8,13,21,34,55)
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Nov 21st, 1999, 12:05 PM
#2
Lively Member
this would entail a writing a function calling itself (recursive)
sub main()
dim ctr,i,j,k as integer
i = 0
j = 1
k = 1
fibGen(i,j,k)
End
sub fibGen(i,j,k as integer)
do
k = i + j
i = j
j = k
ctr = ctr + 1
msgbox(k)
loop while (ctr < 10)
end
hope this would be of help...
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Nov 21st, 1999, 12:14 PM
#3
Lively Member
ops....
missing line...
...
ctr = ctr + 1
msgbox(k)
/* this is the missing line */
fibGen(i,j,k)
loop while (ctr < 10)
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Nov 22nd, 1999, 04:06 AM
#4
I think this should help you
if for some reason it doesn't work at least the F function has the correct algorithm to get what you need.
public sub main()
dim iC,iD as integer
ic=inputbox("Enter the term number you want to get the value of...")
iD=F(iC)
msgbox iD
end sub
private function F(n as integer) as integer
if n=1 or n=2 then
F=1
else
F=F(n-1) + F(n-2)
end if
end function
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Nov 22nd, 1999, 05:50 AM
#5
Thread Starter
Junior Member
Thanks a bunch! It worked without the fibGen(i,j,k)
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kazooie21
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