Finding out if value is numeric

[hurgh]

Hi,
Just wondering, In c, if i use this code snippit:

int value;

printf("Please enter a value: ");
scanf("%d", &value);

how can i then check that value is a numeric value, i know that by declaring it as int it should be numeric, but i have made a menu system that dispalys some options and the user has to enter a number that currosponds to the selection they want to use.

This works great if the user enters a number, but if a user hits a letter key by mistake, then the menu is just displayed over and over again, without stopping.

Maybe i need a way to allow the user to only enter numbers and no letters, is that a possibility, and if so, could you please post some sample code for me (the code needs to be in c, and will be used in a console app)..


Thanks for your help.

-|- Hurgh -|-

[transcendental]

Originally posted by hurgh
Hi,
Just wondering, In c, if i use this code snippit:

char value;

printf("Please enter a value: ");
scanf("%c", &value);

if(value>=48 && value<=57)  //48 to 57 is ascii number for 1-9
{
        value=value-48;
}
else
{
       cout<<"a alphabet is entered, program exits."<<endl;
       return;
}
//do what you want hereafter

The above is kedaman's method. I think is about time I collect some advertising fees from kedaman.

hurgh, if you want to use 10 or above, try to figure out yourself, it is not difficult, ok?

[hurgh]

Thanks for the help, just one last question though

-|- Hurgh -|-