Changing the array size

[abdul]

Is there any way to resize a 1 or 2 dimensional array.
Let us I have:

myarray[5][10]

How can I make it:

myarray[7][15]

after I have declared it and I have also set the values in it?
And also will it delete all the values in the array after I resize it?

[jim mcnamara]

try realloc like this:

void main( void )
{
   long *buffer;
   size_t size;

   if( (buffer = (long *)malloc( 1000 * sizeof( long ) )) == NULL )
      exit( 1 );

   size = _msize( buffer );
   printf( "Size of block after malloc of 1000 longs: %u\n", size );
   buffer[99] = 1;
   printf("%s %ld\n","before realloc buffer[99]=",buffer[99]);

   /* Reallocate and show new size: */
   if( (buffer = (long *)realloc( buffer, size + (1000 * sizeof( long )) )) 
        ==  NULL )
      exit( 1 );
   size = _msize( buffer );
   printf( "Size of block after realloc of 1000 more longs: %u\n", 
            size );
   printf("%s %ld\n","after realloc buffer[99]=",buffer[99]);
   free( buffer );
   return;
}

[Warmaster199]

Just do this:

int myarray[5][10];


In a function do this:


free(myarray); // gets rid of it...
int myarray[7][17]; //makes the array again
// This should do it

Doing this will erase the variable's contents...


I don't think that you can do it Jim's way if you need 2 dimensional arrays... If you absolutely need 2D arrays without using my function and without getting rid of the contents, you need assembler as you can do ABSOLUTELY ANYTHING with assembler...

[abdul]

Thanks guys. It makes sense now