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Thread: When will I become a fanatic member? ;)

  1. May 20th, 2000, 04:27 AM #1
    kinjalgp
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    When will I become a fanatic member?

    Kinjal
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  2. May 20th, 2000, 04:56 AM #2
    NeilAvent
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    you need 500 posts so you best get busy posting if you want it soon.

    I reckon you will get there a long time before I do, thats if I ever do!!
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  3. May 20th, 2000, 06:40 AM #3
    kedaman
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    512, that is 2^9
    Use
    writing software in C++ is like driving rivets into steel beam with a toothpick.
    writing haskell makes your life easier:
    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
    To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
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  4. May 20th, 2000, 07:50 AM #4
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    I don't like this Binary system too much.
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  6. May 20th, 2000, 08:06 AM #5
    kedaman
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    Then what would you prefer, trinary?
    Use
    writing software in C++ is like driving rivets into steel beam with a toothpick.
    writing haskell makes your life easier:
    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
    To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
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  7. May 20th, 2000, 08:28 AM #6
    Guest
    No offense, kedaman, I know it was your idea, bit I personally like the idea of things being rounded to the nearest hundred.
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  8. May 20th, 2000, 06:05 PM #7
    kedaman
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    OK. maybe some people like to have it that way, it's more comfortable with decimal system. But as we're programmers, we should at least not be confused with binary.
    Use
    writing software in C++ is like driving rivets into steel beam with a toothpick.
    writing haskell makes your life easier:
    reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
    To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
    Reply With Quote Reply With Quote
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