help with cash drawer kick open with stored drawer codes in database

[iced8out]

hello, hopefully someone could help me with my issue. this is a point of sale software and it is a touch screen. the issue im having is that when i tap the drawer open button on the screen the cash drawer is not popping open, instead it prints a small receipt with the drawercode that i have stored on the database. however if i embed the drawer code into the sourcecode like this : DrawerCode = Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25) it pops open the drawer perfectly but the issue remains that not everyone who uses the point of sale software is also using the exact make and model of hardware which is why i decided to store drawer codes in the database.

Sub OpenCashDrawer()
        Try
            con = New SqlConnection(cs)
            con.Open()
            cmd = con.CreateCommand()
            cmd.CommandText = "SELECT RTRIM(CashDrawer) from POSPrinterSetting where CashDrawer='Enabled'"
            rdr = cmd.ExecuteReader()
            If Not rdr.Read() Then
                frmCustomDialog11.ShowDialog()
                Exit Sub
            End If
            If (rdr IsNot Nothing) Then
                rdr.Close()
            End If
            If con.State = ConnectionState.Open Then
                con.Close()
            End If
            'Modify DrawerCode to your receipt printer open drawer code
            con = New SqlConnection(cs)
            con.Open()
            cmd = con.CreateCommand()
            cmd.CommandText = "SELECT RTRIM(CDCode) from POSPrinterSetting where CashDrawer='Enabled' and TillID=@d1"
            cmd.Parameters.AddWithValue("@d1", lblTillID.Text)
            rdr = cmd.ExecuteReader()
            If rdr.Read() Then
                DrawerCode = rdr(0).ToString
            End If
            If (rdr IsNot Nothing) Then
                rdr.Close()
            End If
            If con.State = ConnectionState.Open Then
                con.Close()
            End If
            'Modify PrinterName to your receipt printer name
            con = New SqlConnection(cs)
            con.Open()
            cmd = con.CreateCommand()
            cmd.CommandText = "SELECT RTRIM(PrinterName) from POSPrinterSetting where TillID=@d1 and IsEnabled='Yes'"
            cmd.Parameters.AddWithValue("@d1", lblTillID.Text)
            rdr = cmd.ExecuteReader()
            If rdr.Read() Then
                s4 = rdr.GetValue(0)
            End If
            If (rdr IsNot Nothing) Then
                rdr.Close()
            End If
            If con.State = ConnectionState.Open Then
                con.Close()
            End If
            Dim PrinterName As String = s4
            RawPrinter.PrintRaw(PrinterName, DrawerCode)
        Catch ex As Exception
            MessageBox.Show(ex.Message, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error)
        End Try
    End Sub

[jmcilhinney]

First things first, don't use a data reader. If you're retrieving a single value from a database then call ExecuteScalar, not ExecuteReader.

As for the issue, I'm wondering whether it has something to do with the text encoding. I would suggest that you retrieve that data from the database and then compare it to your hard-coded value. The next step depends on whether they are equal or not.

[iced8out]

thanks jmcilhinney for your reply. i went ahead changed it to ExecuteScalar as you suggested. i also compared the code thats prints on the receipt and its exactly as the hard-coded value. yet when i hard code with the same exact drawer code value in to the source code its kicks the drawer instantly without issue. what could you suggest i do to have it kick open the drawer with the drawer code value coming from the database. thank u

[jmcilhinney]

They're obviously not the same or using them would produce the same result. How did you compare them? Did you just look at them? the fact that two things look the same is not proof that they are the same. Did you actually use code to compare the two Strings for equality? Did you compare each Char in the Strings?

[iced8out]

i copied and pasted the code stored in the database and pasted it into the source and it worked. now when i did it the other way where the value comes from the database its prints a receipt with the exact drawer code but doesnt kick open the drawer.

[jmcilhinney]

That's not what I said to do. If you're not going to listen when the help you asked for is provided then I'll waste no more time providing it.

[ChrisE]

i copied and pasted the code stored in the database and pasted it into the source and it worked. now when i did it the other way where the value comes from the database its prints a receipt with the exact drawer code but doesnt kick open the drawer.

try compare again with code

Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
        'Dim str1 As String = "TestString"
        'Dim str2 As String = "teststring"

        Dim str1 As String = "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25)"
        Dim str2 As String = "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25) "

        If String.Compare(str1, str2, StringComparison.Ordinal) = 0 Then
            MessageBox.Show("Are Equal")
        Else
            MessageBox.Show("Are Not Equal")
        End If
    End Sub

[techgnome]

i copied and pasted the code stored in the database and pasted it into the source and it worked. now when i did it the other way where the value comes from the database its prints a receipt with the exact drawer code but doesnt kick open the drawer.

Wait... do you literally have "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25)" in the database? If so, that's your problem. That's not what should be there. What you should have in the database is the characters that are returned by that code, not the code itself.\


-tg

[iced8out]

try compare again with code

Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
        'Dim str1 As String = "TestString"
        'Dim str2 As String = "teststring"

        Dim str1 As String = "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25)"
        Dim str2 As String = "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25) "

        If String.Compare(str1, str2, StringComparison.Ordinal) = 0 Then
            MessageBox.Show("Are Equal")
        Else
            MessageBox.Show("Are Not Equal")
        End If
    End Sub

hi chris thank you for your reply, i ran your code and i got the message that " not equal"

[iced8out]

Wait... do you literally have "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25)" in the database? If so, that's your problem. That's not what should be there. What you should have in the database is the characters that are returned by that code, not the code itself.\


-tg

hi techgnome, thank you for your reply. yes i have the code literally "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25)" in the database because i dont how to store it in the database any other way. if you could give me a better way to do it i would be greatly appreciate it. ive tried removing the "chr" and putting it in like this : (27)(7)(11)(55)(25) but same result, ive tried also : Chr(27) Chr(7) Chr(11) Chr(55) Chr(25) but also no luck.

[OptionBase1]

hi techgnome, thank you for your reply. yes i have the code literally "Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25)" in the database because i dont how to store it in the database any other way. if you could give me a better way to do it i would be greatly appreciate it. ive tried removing the "chr" and putting it in like this : (27)(7)(11)(55)(25) but same result, ive tried also : Chr(27) Chr(7) Chr(11) Chr(55) Chr(25) but also no luck.

Imagine your password to a website is 200, should the system accept a password of "Two Hundred"? That should demonstrate why what you are trying isn't going to work.

I'm not motivated enough to fire up my box that has SQL on it to try it, but I'm going to assume that storing the non-printable low ascii characters as-is won't work.

If this were me, I'd probably store it as:

27,7,11,55,25

in SQL, retrieve it in VB, split it into an array, and then use Chr() on the array values to build the string. That being said, there's likely more elegant ways to do it than that.

[jmcilhinney]

Good grief! What Chr does is create a Char value from an ASCII code and your code here:

DrawerCode = Chr(27) & Chr(7) & Chr(11) & Chr(55) & Chr(25)

creates a String containing those characters. It's that String that you should be saving to the database. I'm sure that you're quite capable of working out how to save a String to a database. Alternatively, you could convert the String to a Byte array using Encoding.ASCII.GetBytes and then store that as binary data in the database, calling Encoding.ASCII.GetString in your application. That extra step seems a bit pointless though.

[.paul.]

hi chris thank you for your reply, i ran your code and i got the message that " not equal"

Chr(80) = “P”

But

“Chr(80)” <> “P”

Why??? Check the quotation marks. Anything contained within double quotation marks is a String literal