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Mar 26th, 2020, 09:15 AM
#3
Re: Pattern: 1 2 6 14 27 46 72
First step is to see if the differences of terms gives any insight into any formula used to generate the terms:
1 2 6 14 27 46 72
1st differences: 1 4 8 13 19 26
2nd differences: 3 4 5 6 7
3rd differences: 1 1 1 1
Since the 3rd differences are all equal, that means the formula used to generate the terms is of 3rd degree in the form of:
A(x) = a*x^3 + b*x^2 + c*x + d
You have been given A(1) = 1, A(2) = 2, A(3) = 6, A(4) = 14, ...
Using those given values, you can build a series of simultaneous equations that allow you to solve for the values of the coefficients a, b, c, and d.
a + b + c + d = 1
8*a + 4*b + 2*c + d = 2
27*a + 9*b + 3*c + d = 6
64*a + 16*b + 4*c + d = 14
That's as far as I'll go for now. Good luck!
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