Regular Expression: "ng" followed by [aeiou] should be a match by itself

[dee-u]

The first commented regular expression almost fits my need, except I need it to find "ng" followed by either a,e,i,o,u as a match itself. Been trying for hours to no avail.

Example:
tanga should return "ta" and "nga"
nganga = nga nga
amboy = am boy
tomboy = tom boy

var bla;

bla = "nganga";

var result;
//var syllableRegex = /[^aeiou]*[aeiou](?:[^aeiou]*$|[^aeiou](?=[^aeiou]))?/gi;
var syllableRegex = /[^aeiou]*[aeiou](?:[ng](?=aeiou)*$|[^aeiou]*$|[^aeiou](?=[^aeiou]))?/gi

while (result = syllableRegex.exec(bla)) 
{
  var Match = result[0];
  alert(Match);
  alert(syllableRegex.lastIndex);
}

Any help will be greatly appreciated.

[PlausiblyDamp]

Not quite sure I follow what the regex is trying to do, I can see how the "nganga" examples matches "ng" followed by a vowel but I am not sure how the others fit into the pattern.

[dee-u]

This is the original regex I am using:

/[^aeiou]*[aeiou](?:[^aeiou]*$|[^aeiou](?=[^aeiou]))?/gi

First, zero or more consonants: [^aeiou]*
Then, one or more vowels: [aeiou]+
After that, zero or one of the following:
Consonants, followed by the end of the word: [^aeiouy]*$
A consonant (if it is followed by another consonant): [^aeiouy](?=[^aeiouy])

As I've said, it almost fit my need but I need to modify it so that "nga, nge, ngi, ngo, ngu" should be their own match, disregarding the expression above. Here is what I came up but it returns the match of "^aeiou]*[aeiou]" followed by "nga, nge, ngi, ngo, ngu":

/[^aeiou]*[aeiou](?:(nga|nge|ngi|ngo|ngu)|[^aeiou]*$|[^aeiou](?=[^aeiou]))?/gi;

My workaround is to divide the returned word:

var NGPosition = Match.indexOf("ng");
				if (NGPosition > 0)
				{
					var str1 = Match.substr(0,NGPosition);
					var str2 = Match.substr(NGPosition, Match.length - NGPosition);

It appears to work in my initial tests but I would really like to make it a regex if possible.