simple conversion?

[MPrestonf12]

how can I convert a float to a char?

[crptcblade]

you could cast it as an int:

char chrTest = (int)(3.2); 

[MPrestonf12]

i tried

char sztext = (int)(result);

MessageBox(NULL,sztext,"testing",MB_OK);

it says as a error-annot convert parameter 2 from 'char' to 'const char *'

[crptcblade]

char* sztext = (int)(result);

MessageBox(NULL,sztext,"testing",MB_OK);

try that

[MPrestonf12]

tryed that earlier I get the error

cannot convert from 'int' to 'char *'.

also I mistyped- Im converting double to char if it matters.

[crptcblade]

note that that will display the 3rd ASCII character. I fyou what to convert 3.2 into "3.2", then I would suggest using the itoa() function

[MPrestonf12]

but won't that truncate 3.2 to 3?

[jim mcnamara]

t'ash dee aay yah. (except the char set doesn't support Athapascan symbols..)

Trans: Is that all there is....

use sprintf.

void main( void )
{
   char  buffer[200], s[] = "computer", c = 'l';
   int   i = 35, j;
   float fp = 1.7320534f;

   /* Format and print various data: */
   j  = sprintf( buffer,     "\tString:    %s\n", s );
   j += sprintf( buffer + j, "\tCharacter: %c\n", c );
   j += sprintf( buffer + j, "\tInteger:   %d\n", i );
   j += sprintf( buffer + j, "\tReal:      %f\n", fp );

   printf( "Output:\n%s\ncharacter count = %d\n", buffer, j );
} 

[MPrestonf12]

thanks, also when i want to make it so it only displays two digits after the decimal point I know I use cout.precison(2), right? I used it and it made no difference.