Rounding value

[mohammedkhairy]

Hello, m8
I want to know what is the equation which round 7.33 to 7.35 or 7.67 to 7.70
meaning round the 2nd decimal number to the nearest five
Thank you

[jmcilhinney]

Firstly, that isn't rounding the second decimal number to the nearest five or else 7.67 would become 7.65. So, do you actually want to round or specifically round up?

Either way, there's no one method to that exactly. You would have to multiply, then round or ceiling, then divide. Exactly how depends on whether you want to round or ceiling.

[mohammedkhairy]

Firstly, that isn't rounding the second decimal number to the nearest five or else 7.67 would become 7.65. So, do you actually want to round or specifically round up?

Either way, there's no one method to that exactly. You would have to multiply, then round or ceiling, then divide. Exactly how depends on whether you want to round or ceiling.

Thank you for your reply
I want to round up whatever the value of the second decimal number to nearest five (7.01 to 7.05 or 7.333 to be 7.35 and 7.61 to be 7.65) like that not to the least value.
in EXCEL the CEILING function is doing that by Ceiling(cell number , 0.05)

but how can I do it in VB.net

[jmcilhinney]

In VB.NET you would use the Math.Ceiling method. It only rounds to whole numbers though, so you'll need to multiply first and then divide afterwards.

[mohammedkhairy]

In VB.NET you would use the Math.Ceiling method. It only rounds to whole numbers though, so you'll need to multiply first and then divide afterwards.

Can you please do an example showing the method

[jmcilhinney]

Can you please do an example showing the method

Why can't you make an effort to do it for yourself? I've told you what to do. Just do it.

[mohammedkhairy]

Why can't you make an effort to do it for yourself? I've told you what to do. Just do it.

Thank you, for our effort
but I'm new using VB.NET, what I understand from your answer that I should use MATH.CEILING, which will round the positive value to the next bigger integer number " 7.333 will be 8" .
But I don't understand what do you mean by

you'll need to multiply first and then divide afterwards

[si_the_geek]

As an example:

If you multiply 7.333 by 100 it becomes 733.3
The Ceiling of that is 734
Divide that by the same as you multiplied by (in this case 100), and the result is 7.34

What you need to do is work out what number to multiply/divide by.

As with many programming problems, this kind of thing is not specific to VB.Net or even to programming.

[mohammedkhairy]

As an example:

If you multiply 7.333 by 100 it becomes 733.3
The Ceiling of that is 734
Divide that by the same as you multiplied by (in this case 100), and the result is 7.34

What you need to do is work out what number to multiply/divide by.

As with many programming problems, this kind of thing is not specific to VB.Net or even to programming.

Thank you,
But it will only round to the bigger value 734 or 761 I need it to be 735 or 765 (to the nearest five)

[si_the_geek]

If you multiply (and divide) by 100, then yes... but that is why I wrote the second half of my post:

What you need to do is work out what number to multiply/divide by.

As with many programming problems, this kind of thing is not specific to VB.Net or even to programming.

While we could do it all for you, that would mean you are less likely to learn/understand.

[mohammedkhairy]

If you multiply (and divide) by 100, then yes... but that is why I wrote the second half of my post:


While we could do it all for you, that would mean you are less likely to learn/understand.

Ok, Thank you
I will try and l hope solve this problem
Thanks for your concern again

[techgnome]

IF you are going UP to the next .05 ... which isn't rounding... try this:

	Public Sub Main()
		dim someNum as Decimal =7.5151 '5.01
		
		Console.WriteLine(someNum.ToString())
		someNum *= 100 '751.51
		Console.WriteLine(someNum.ToString())
		someNum = Math.Ceiling(someNum) '752\
		Console.WriteLine(someNum.ToString())
		someNum += (5- ((someNum + 5) mod 5)) '<--- this is the key here
		
		'Console.WriteLine((5-((someNum + 5) mod 5)).ToString)
		
		Console.WriteLine(someNum.ToString())
		someNum /= 100		
		Console.WriteLine(someNum.ToString())
		
	End Sub

https://dotnetfiddle.net/06Vzyf

PArt of the issue is you keep calling it rounding, but that isn't what you're looking for... at any rate, this gives you the results you defined with your excel screen shot. There is a little more to it than just the multiply/divide ... you also need to figure how far off from the next 5 you are. I've done this by adding 5, using mod to get the remainder, then subtracting that from 5 and adding it back to the original number. There might be a way to simplify it.

Using the above, I got 7.55 and 5.05 for the final results.

-tg

[si_the_geek]

There's no need for Mod etc, just picking the right number (which is less than 100, and is the reciprocal of the 'rounding' amount) is enough.

[mohammedkhairy]

IF you are going UP to the next .05 ... which isn't rounding... try this:

	Public Sub Main()
		dim someNum as Decimal =7.5151 '5.01
		
		Console.WriteLine(someNum.ToString())
		someNum *= 100 '751.51
		Console.WriteLine(someNum.ToString())
		someNum = Math.Ceiling(someNum) '752\
		Console.WriteLine(someNum.ToString())
		someNum += (5- ((someNum + 5) mod 5)) '<--- this is the key here
		
		'Console.WriteLine((5-((someNum + 5) mod 5)).ToString)
		
		Console.WriteLine(someNum.ToString())
		someNum /= 100		
		Console.WriteLine(someNum.ToString())
		
	End Sub

https://dotnetfiddle.net/06Vzyf

PArt of the issue is you keep calling it rounding, but that isn't what you're looking for... at any rate, this gives you the results you defined with your excel screen shot. There is a little more to it than just the multiply/divide ... you also need to figure how far off from the next 5 you are. I've done this by adding 5, using mod to get the remainder, then subtracting that from 5 and adding it back to the original number. There might be a way to simplify it.

Using the above, I got 7.55 and 5.05 for the final results.

-tg

Thank you very much, your answer is very clear and I understand it

There's no need for Mod etc, just picking the right number (which is less than 100, and is the reciprocal of the 'rounding' amount) is enough.

Thanks, I multiply the value with 20 and ceiling it then divided it by 20 and get the answer

Dim x as decimal
x = math.ceiling(7.33333*20)
textbox?.text = x/20
' 7.33 >> 7.35

[si_the_geek]

That's it, well done