change vb6 byte array default range

[RumblefishX]

i'm making a program that will export some data like a byte array...

the program array is coded in VB6 and stored in database, but i need to read this data through java program.

In vb6 we have the byte array filled by values that start at number 0 to number 255, but in the java the range is -127 at 128.

Using vb6, how can i let the vb6 byte array on the java standard?

[dilettante]

The VB6 Byte type is an unsigned 8-bit integer.

Nothing prevents you from stuffing any bit pattern in there that you want. One possibility is to use VB6's Integer type (signed 16-bit integer) and move the lower 8 bits of that into a Byte.

Such moves could be done a number of ways (GetMem1/PutMem1, CopyMemory, UDTS and LSet, etc.). The only tricky part may be moving back from a negative "signed byte" value into an Integer. Then you need to check the high bit of the Byte value and if set be sure to move &HFF into the high byte of the Integer variable as well as copying the Byte into the low byte.

[passel]

It sounds like the byte array is already in the database, put in from VB6.
You stated the range incorrectly, it would be -128 to 127 on the Java side.
If the meaning of the value has to have its VB6 meaning, i.e. 0 to 255 when read on the Java side, then I would read the data into a Java byte array, then loop through and set elements of an Integer array to the value in the byte array + 128.
If you had to write back to the database, then you would loop through the integer array and set the byte array value to integer value - 128.

Rereading the post, I guess it you want the VB6 side to treat the numbers as -128 to 127, then as dilettante has already said, use integers on the VB6 side to maintain the -128 to 127 values.
But you can still set just set the bytes in a byte array to the integer value + 128, before sending the byte array to the database, and do the reverse when reading them on the VB6 side.