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Thread: Parse error.

  1. Aug 3rd, 2001, 04:18 AM #1
    Mobic
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    Parse error.

    Code:
    10. <?
11. IF ($submit")

13. $host = "www.freesql.org";
14. $user = "mobic";
15. $pass = "*";
16. {mysql_pconnect ("$host","$user","$pass");
17. mysql_select_db("war");
18. $sql = "insert into brukere(fornavn, etternavn, brukernavn, 19. passord) values    ('$fornavn','$etternavn', '$brukernavn', '$passord')";

20. $result = mysql_query($sql);
21. $ID = mysql_insert_id();
22. Print("Konto opprettet!");
23. ?>
    From this I get:
    Parse error: parse error in /register.php on line 11
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  2. Aug 3rd, 2001, 04:20 AM #2
    chenko
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    IF ("$submit")
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  3. Aug 3rd, 2001, 04:23 AM #3
    Mobic
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    I've tried that, but then i got the same error on line 26, and there is only 25 lines.
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  4. Aug 3rd, 2001, 04:30 AM #4
    chenko
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    post the rest of your code then....
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  6. Aug 3rd, 2001, 08:13 AM #5
    Mobic
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    [code]
    <html>
    <head></head>
    <body><form method="post" action="registrer.php">
    Fornavn: <input type="text" name="fornavn"><br>
    Etternavn: <input type="text" name="etternavn"><br>
    Brukernavn: <input type="text" name="brukernavn"><br>
    Passord: <input type="text" name="passord"><br>

    <input type="Submit" name="submit" value="Registrer"><br> </form>
    <?
    IF ("$submit")

    $host = "www.freesql.org";
    $user = "mobic";
    $pass = "*";
    {mysql_pconnect ("$host","$user","$pass");
    mysql_select_db("war");
    $sql = "insert into brukere(fornavn, etternavn, brukernavn, passord) values ('$fornavn','$etternavn', '$brukernavn', '$passord')";

    $result = mysql_query($sql);
    $ID = mysql_insert_id();
    Print("Konto opprettet!");
    ?>
    </body>
    </html>
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  7. Aug 3rd, 2001, 06:44 PM #6
    scoutt
    Guest
    try this
    PHP Code:
    IF ("$submit") {

    $host = "www.freesql.org"; 
    $user = "mobic"; 
    $pass = "*"; 
    {    mysql_pconnect ("$host","$user","$pass"); 
    mysql_select_db("war"); 
    $sql = "insert into brukere(fornavn, etternavn, brukernavn, passord) values ('$fornavn','$etternavn', '$brukernavn', '$passord')"; 

    $result = mysql_query($sql); 
    $ID = mysql_insert_id(); 
    Print(    "Konto opprettet!"); 
    }else{
    print    "what ever you want to do if it was not submit";
    } 
    it looks like it was looking for something else. try that code
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  8. Aug 4th, 2001, 09:02 AM #7
    Psyrus
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    Shouldn't there be a closing } somewhere after this line?

    {mysql_pconnect ("$host","$user","$pass");
    Chris

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    Don't forget to rate people if they helped you.
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  9. Aug 4th, 2001, 10:38 AM #8
    Mobic
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    Thanks, it works fine now
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