2 C++ ??: 1) a Val() equivalent? 2) a conversion list?

[wengang]

Hi all.
I am just beginning my study of (Visual) C++ this week. I was re-writing a calculator I wrote in VB when I was just begiinning VB.

So is there a C++ equivalent to Val() ?

I found strtod(a,b) which seems to be the equivalent of
vb's Cdbl(x) .

Anyway, I can't get strtod to work. I just don't get it and the MSDN example doesn't make sense.
So I have a string with a numerical value like "500"
and I want to move that to a double like
dblNumber = strtod(strNumber,????)
and everything I put in the 2nd parameter creates errors.

Okay, 2nd question, is there a place I can find a keyword (key function) conversion list for VB and C++? I think that would help the most.

Thanks all.
Wengang

[CyberCarsten]

Try declaring the numerical variable as an integer

int SomeValue;

[kedaman]

So is there a C++ equivalent to Val() ?

probably not. Val does many other opererations besides converting unicode strings to variant numeric datatypes

Okay, 2nd question, is there a place I can find a keyword (key function) conversion list for VB and C++? I think that would help the most.

many vb functions doesn't exist in c++, however there are libraries with algoritms that perform more specific actions.

i think you have to pass a double pointer in ???? place, if you declare a double x, you pass &x

[CornedBee]

ad 1:
The second param is of type char **ppEndPtr. This means it's a pointer to a pointer to a character. This works the following way:
Pass the string "347.28aiw" to strtod. The function will extract 347.28 and stop at the 'a', since it is not a number. The function will the set the *ppEndPtr to the 'a', so you know afterwards until where the function did read the string. You can either pass NULL or like this:
char* str = "279.18aiw";
char* pEndChar;
double val = strtod(str, &pEndChar);

ad 2:
You can always ask us if you need a funciton equivalent.

All the buzzt
CornedBee

[Vlatko]

Well yes there are some VB functions that don't exist in C++ but they call all be improvised.