How to centre the graphic in the picture box

[matrik02]

How to centre the graphic draw in the picture box?

Picture1.Line (Text1.Text, Picture1.ScaleHeight - Text2.Text)-(Text3.Text, Picture1.ScaleHeight - Text4.Text), vbBlue
Picture1.FillStyle = 0
Picture1.FillColor = vbRed
Picture1.Circle (Text1.Text, Picture1.ScaleHeight - Text2.Text), 100
Picture1.FillStyle = 0
Picture1.FillColor = vbRed
Picture1.Circle (Text3.Text, Picture1.ScaleHeight - Text4.Text), 100
Picture1.Line (Text3.Text, Picture1.ScaleHeight - Text4.Text)-(Text5.Text, Picture1.ScaleHeight - Text6.Text), vbBlue
Picture1.FillStyle = 0
Picture1.FillColor = vbRed
Picture1.Circle (Text5.Text, Picture1.ScaleHeight - Text6.Text), 100
Picture1.Line (Text5.Text, Picture1.ScaleHeight - Text6.Text)-(Text7.Text, Picture1.ScaleHeight - Text8.Text), vbBlue

[Doogle]

I believe that the center of a PictureBox is
x= Picture1.ScaleWidth / 2 , y = Picture1.ScaleHeight / 2

[LaVolpe]

The algo for centering anything on a background object

centerX = (bkgObj.Width - tgtObj.Width) \ 2
centerY = (bkgObj.Height - tgtObj.Height) \ 2

[Spoo]

Matrick

In addition to the foregoing posts, I'll mention that
I've found the graphic method specs somewhat "obtuse".

So I create generic subs that make it easier for me to
establish the various paremeters. For example:

... for a Line

Sub ZLINE(nXX1, nXX2, nYY1, nYY2, nDW, nCC)
    '
    With PB1
        .DrawStyle = 0
        .DrawWidth = nDW
        PB1.Line (nXX1, nYY1)-(nXX2, nYY2), nCC
    End With
    '
End Sub

... for a Circle

Sub ZCIRC(nXX1, nYY1, nDW, nRADIUS, nCC)
    '
    With PB1
        odw = .DrawWidth
        .DrawWidth = nDW
        PB1.Circle (nXX1, nYY1), nRADIUS, nCC
        .DrawWidth = odw
    End With
    '
End Sub

Then, in the calling sub, to draw your graphics,
(not centered yet) I would do this..

xx1 = Val(Text1.Text)
xx2 = Val(Text3.Text)
yy1 = Val(Text2.Text)
yy2 = Val(Text4.Text)
'
ZLINE xx1, xx2, yy1, yy2, 1, vbBlue
ZCIRC xx1, yy1, 1, 100, vbRed
ZCIRC xx2, yy2, 1, 100, vbRed
'
' etc
'

To deal with the centering requirements, I would
modify the code as follows by applying offsets

With PB1
    ' raw coords
    xx1 = Val(Text1.Text)
    xx2 = Val(Text3.Text)
    yy1 = Val(Text2.Text)
    yy2 = Val(Text4.Text)
    ' calc offsets
    lenX = xx2 - xx1
    lenY = yy2 - yy1
    cenX = xx1 + lenX / 2
    cenY = yy1 + lenY / 2
    cenXpb = .Width / 2
    cenYpb = .Height / 2
    oox = cenXpb - cenX 
    ooy = cenYpb - cenY
    ' apply offsets
    xx1o = xx1 + oox
    xx2o = xx2 + oox
    yy1o = yy1 + ooy
    yy2o = yy2 + ooy
    ZLINE xx1o, xx2o, yy1o, yy2o, 1, vbBlue
    ZCIRC xx1o, yy1o, 1, 100, vbRed
    ZCIRC xx2o, yy2o, 1, 100, vbRed
    '
End With

I have not tested this.

It is a admittedly "brute force" approach, but I
hope that it gives you some ideas.

Spoo

[DataMiser]

The algo for centering anything on a background object

centerX = (bkgObj.Width - tgtObj.Width) \ 2
centerY = (bkgObj.Height - tgtObj.Height) \ 2

Yes, I would add however that in some cases you need to use the scalewidth and scaleheight of the background object to get the correct results.

[matrik02]

I would like to draw the line at the centre of picture box. Mybe I would like to move the line I drew to the center of picturebox

Picture1.Line (Text1.Text, Picture1.ScaleHeight - Text2.Text)-(Text3.Text, Picture1.ScaleHeight - Text4.Text), vbBlue
Picture1.FillStyle = 0
Picture1.FillColor = vbRed
Picture1.Circle (Text1.Text, Picture1.ScaleHeight - Text2.Text), 100
Picture1.FillStyle = 0
Picture1.FillColor = vbRed
Picture1.Circle (Text3.Text, Picture1.ScaleHeight - Text4.Text), 100
Picture1.Line (Text3.Text, Picture1.ScaleHeight - Text4.Text)-(Text5.Text, Picture1.ScaleHeight - Text6.Text), vbBlue
Picture1.FillStyle = 0
Picture1.FillColor = vbRed
Picture1.Circle (Text5.Text, Picture1.ScaleHeight - Text6.Text), 100
Picture1.Line (Text5.Text, Picture1.ScaleHeight - Text6.Text)-(Text7.Text, Picture1.ScaleHeight - Text8.Text), vbBlue

[Spoo]

Matrik

Your post #6 appears to be the same as your OP (post #1)

Did you happen to notice my post #4?

If you did but felt it was too "obtuse", so be it .. no problem
But, if you did and have some questions, I'll be glad to expand.

Spoo