Quote Originally Posted by jemidiah View Post
You're written the question very strangely. It's hard to reconstruct.

I imagine the number of events per day t is given by n = n0 + bt, where n0=5 and b=2. I have no idea why you wrote t=10--actually maybe that's supposed to be the last day data was collected? I don't know what PDF you want. The average number of events per day from this data is at least easy to calculate:

[(n0 + b*0) + (n0 + b*1) + ... + (n0 + b*10)]/11
= [11*n0 + b*(0+1+...+10)]/11
= [11*n0 + 10*11/2*b]/11
= n0 + 5b
= 5 + 10
= 15
= M

The mean squared error here is just the average of the squared difference between the mean M and each data point. The data points are n0 + b*0, ..., b0 + b*10 = 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, which have differences (magnitude only) of 10, 8, 6, 4, 2, 0, 2, 4, 6, 8, 10, which have squares 100, 64, 36, 16, 4, 0, 4, 16, 36, 64, 100, which have average 440/11 = 40.



By the way, I almost arbitrarily started this data at t=0. The given function would still give a positive number of events at t=-1.
Thanks Sir,
I was not able to initiate it .Even i have tried it solve but was unsuccessful.As u have explained it well So thanks for it .I hope you will try to solve my further questions.