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Thread: [RESOLVED] String assistance

  1. #1

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    Resolved [RESOLVED] String assistance

    I have a button which places text into a text box which is then copied to emails.

    here is the code:

    TextBox40.Text = "IP Address :" & Ip & vbCrLf & "Default Gateway:" & Gw & vbCrLf & "Subnet Mask :" & Sm & vbCrLf & "DNS Servers :" & Dns

    which results in:

    IP Address :
    Default Gateway:
    Subnet Mask :
    DNS Servers :

    I'm trying to make the colons line up in a straight line vertically but can't seem to get them to match.

    Any ideas?

  2. #2
    Discovering Life Siddharth Rout's Avatar
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    Re: String assistance

    What I would suggest is to create your own userform and then use labels to show that text. It will be very simple to align the text that ways
    A good exercise for the Heart is to bend down and help another up...
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  3. #3

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    Re: String assistance

    That will work, thanks.

    Any idea why I can't get the last 3 characters removed with this condition?

    If Right(test, 3) = "/##" Then
    MsgBox Left(test, (Len(test) - 3))
    End If

  4. #4
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    Re: String assistance

    works for me
    make sure no spaces at end of string

    there is also sendmessage API with em_settabs
    to align text in textbox
    i do my best to test code works before i post it, but sometimes am unable to do so for some reason, and usually say so if this is the case.
    Note code snippets posted are just that and do not include error handling that is required in real world applications, but avoid On Error Resume Next

    dim all variables as required as often i have done so elsewhere in my code but only posted the relevant part

    come back and mark your original post as resolved if your problem is fixed
    pete

  5. #5
    Discovering Life Siddharth Rout's Avatar
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    Re: String assistance

    Quote Originally Posted by jsublime View Post
    That will work, thanks.

    Any idea why I can't get the last 3 characters removed with this condition?

    If Right(test, 3) = "/##" Then
    MsgBox Left(test, (Len(test) - 3))
    End If
    What is the value of 'test'?
    A good exercise for the Heart is to bend down and help another up...
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  6. #6

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    Re: String assistance

    dim test as String

    test=textbox41.text

  7. #7
    Discovering Life Siddharth Rout's Avatar
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    Re: String assistance

    And what is the value of textbox41.text ?
    A good exercise for the Heart is to bend down and help another up...
    Please Mark your Thread "Resolved", if the query is solved


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  8. #8

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    Re: String assistance

    ive been testing it with various entries similar to 55.55.55.100 and 55.55.55.100/30

  9. #9
    Discovering Life Siddharth Rout's Avatar
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    Re: String assistance

    I could be wrong but I guess what you are trying to do is 'String Comparison'...

    Here is an example of what I think you want... (In case I am wrong, then ignore this post...)

    Code:
    Sub Sample()
        Dim StrSample As String
        StrSample = "55.55.55.100/30"
        
        If Right(StrSample, 3) Like "/##" Then
            MsgBox Left(StrSample, (Len(StrSample) - 3))
        End If
    End Sub
    Last edited by Siddharth Rout; Oct 11th, 2010 at 01:36 PM.
    A good exercise for the Heart is to bend down and help another up...
    Please Mark your Thread "Resolved", if the query is solved


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  10. #10

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    Re: String assistance

    Interesting, that worked. Thanks!

  11. #11
    Discovering Life Siddharth Rout's Avatar
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    Re: String assistance

    Glad your query is solved

    Do remember to mark the thread resolved

    Check my signature on how to mark the thread resolved
    A good exercise for the Heart is to bend down and help another up...
    Please Mark your Thread "Resolved", if the query is solved


    MyGear:
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    ★ Cooling ★ NOCTUA NH-D15 CHROMAX BLACK 140mm + 10 of Noctua NF-F12 PWM
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