Reversed Integer Using Arrays, My friend told me its to complicated

[sl02ggp]

The assignment everyone has done before..lol...reversing digits. How do i make my code more simple (as my friend stated)?

Trying to write a program that reverses the digits in an integer. Assuming that the max value of the integer is 99999. And using arrays to solve the problem.

For example if integer:
0 was entered, output is 0
10 was entered, output is 1
12 was entered, output is 21
123 was entered, output is 321
7600 was entered, output is 67
8015 was entered, output is 5108
90000 was entered, output is 9

here is my code:

#include <stdio.h>
#include <math.h>

int main()
{
      int intnumber, condition, remainder;
      int counter = 0, i = 0, j = 0, counter1 = 0;
      int reverseint[99999];       

	  printf("Enter an integer number: ");
      scanf_s("%d", &intnumber);
      condition = intnumber;  

	  while (condition > 0)
      {
         condition  = condition /10;
         counter = counter + 1;
         counter1 = counter1 + 1;
      } 

	  counter = counter - 1;
      printf("The number in reverse: ");
      while (counter >= 0)
     {
         remainder = intnumber % (int) pow(10, counter);
         intnumber = intnumber/(int) pow(10,counter);     
		 reverseint[i] = intnumber;
         i++;
         intnumber = remainder;
         counter = counter - 1;
      }

      for(j=counter1-1;j >= 0;j--)
	  {
         printf("%d ", reverseint[j]);
		 printf("\n");
	  }  
}

[sl02ggp]

I found out that, I can't use printf but instead use couts.
I'm in a beginner level's C++ class and my teacher also wants it more simpler..aha

said i can't use scanf_s, pow, and strings!?!?!