[RESOLVED] Regex? Get content within " "

[Disyne]

I have a string that contains text similar to this:

hello "test" "another test\"" "ok"

I want it to split in an output like this:

test
another test\"
ok

In this thread http://www.vbforums.com/showthread.php?t=576158 (?<=[^\\]|^)"" was used to remove quotes that don't have a \ before them. Maybe it can be adapted to be used as a split? But I am unsure on how to do so.

Thanks in advance.

[ForumAccount]

'hello' gets deleted because it's not in double quotes?

[Disyne]

Yes.

[Empyreal]

I'm not a genius with regexp, but this should work:

"[a-z ]*\\?"?"

Although, you will have to remove the beginning and ending quotation marks:

String = String.Remove(0,1)
String = String.Remove(String.Length - 1, 1)

[ForumAccount]

What happens if a string isn't terminated properly with double quotes? ie:

this is" just a "test" "example \"

[Empyreal]

Lol, didn't take that into consideration =P

There need to be clearer rules in case something like that occurs. Should it print:

" just a "test"
"example \"

Or should it just remove one of the quotation marks? Which one?

I.e.

"test"
"example \"

or

" just a test"
"example \"

etc..

[Disyne]

If it is something like this:
"hello " hi"
You should get
hello
(with a space after hello) It should return the first set of double quotes.

If it is: "hello \" it should return: hello \
If that is even possible without making it extremely complicated while still being able to maintain:
"hello \" hi"
Being: hello \" hi
Otherwise if that is to complicated make it return nothing.

[Empyreal]

Would this be more suited to your needs?

"[a-z \\]*"?[a-z \\]*"