Sqr And Sqrt

[VbNooBie447]

i tried using the SQR function in VB,and it gave me a wrong answer. i did some search and i got this:

# SQR
The square function returns the square (ie the argument multiplied by itself) of its supplied argument,


SQR( 2 ) returns 4

# SQRT
This function returns {always returns a real} the square root of its argument, eg,


SQRT( 4 ) returns 2.0000000000E+00



could someone explain how would i use each of these two functions in VB?

[LaVolpe]

There is no SQRT in VB, I do not know what you were referencing
SQR in VB: Returns the square root of a number
To return the square: 4 * 4, or 4 ^ 2

[VbNooBie447]

so for example i have this equation i want to calculate in VB:

4*Sqrt((98*800*1.00)/(4*Sqr(230)*Sin(Rad(2*70))))

[LaVolpe]

Replace Sqr(230) with (230*230)
Then replace Sqrt with SQR
There is also no RAD function in VB.

[VbNooBie447]

how would i declare RAD?

[Hack]

Other than Rapid Application Development, what is RAD?

[VbNooBie447]

in math, it means radian

i dimmed as double and added Rad=57.2958

now im trying to do it with this equation:

2*(ABS(46*800+SIN(PI()/180*-1)*1*800-COS(PI()/180*-1)*1*0))/(sqr(2*2)*175*sqrt(((46+SIN(PI()/180*-1)*1)*COS(PI()/180*-81)-COS(PI()/180*-1)*1*SIN(PI()/180*-81))*(0*COS(PI()/180*-81)-800*SIN(PI()/180*-81))))

i got everything right, except for this part: sqrt(((46+SIN(PI()/180*-1)*1), and for the PI, i declared the PI as double and everything but it gives me "expected array" error

[Hack]

In case others might be interested, I found this

http://www.devx.com/vb2themax/Tip/19029