[RESOLVED] How to find in returns(vbcrlf) in VBA

[cutepraba]

With Selection.Find
    .Text = vbCrLf & vbCrLf
    .Replacement.Text = ""
    .Forward = True
    .Wrap = wdFindContinue
    .Format = False
    .MatchCase = False
    .MatchWholeWord = False
    .MatchWildcards = False
    .MatchSoundsLike = False
    .MatchAllWordForms = False
End With
MsgBox Selection.Find.Execute

The above code returing false value. please help me to replace two ENTERS to one ENTER.

[dmaruca]

With Selection.Find
    .Text = "^13^13"
    .Replacement.Text = "^p"
    .Forward = True
    .Wrap = wdFindContinue
    .Format = False
    .MatchCase = False
    .MatchWholeWord = False
    .MatchWildcards = True
    .MatchSoundsLike = False
    .MatchAllWordForms = False
End With
MsgBox Selection.Find.Execute

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[anhn]

    With ActiveDocument.Range.Find
        .Forward = True
        .Wrap = wdFindContinue
        .Format = False
        .MatchCase = False
        .MatchWholeWord = False
        .MatchWildcards = False
        .MatchSoundsLike = False
        .MatchAllWordForms = False
        Do
            .Text = "^p^p"
            .Replacement.Text = "^p"
        Loop Until .Execute = False
    End With

[cutepraba]

then how to find string ^13.

please dont mistake me, I am just asking

[cutepraba]

    With ActiveDocument.Range.Find
        .Forward = True
        .Wrap = wdFindContinue
        .Format = False
        .MatchCase = False
        .MatchWholeWord = False
        .MatchWildcards = False
        .MatchSoundsLike = False
        .MatchAllWordForms = False
        Do
            .Text = "^p^p"
            .Replacement.Text = "^p"
        Loop Until .Execute = False
    End With

thank you