Need help pls 'fraction division in VB 2005

[ChemEng]

Hello,,,,,,,,,,,,,,,

Would some1 please help me to let the below code work for proper fractions( positive numbers less than 1)

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim D1, D2 As Integer
D1 = CInt(TextBox1.Text)
D2 = CInt(TextBox2.Text)

TextBox3.Text = D2 / D1

End Sub
End Class

If I put 0.1 in textbox2 and 0.3 in textbox1 the results in textbox3 is NaN ??!!!


Cheers

[Pradeep1210]

That's because you are converting to Integer before division. You should use SINGLE, DOUBLE or DECIMAL datatype to handle decimal points.

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
    Dim D1, D2 As Double
    D1 = CDbl(TextBox1.Text)
    D2 = CDbl(TextBox2.Text)
 
    TextBox3.Text = D2 / D1
 
End Sub
End Class

[ChemEng]

Loads of cheers Pradeep1210. It's really working now. I just unable to find the way to rate the answer u posted, otherwise it is 10/10.

many thanks.

[Zach_VB6]

Click this button:

[ChemEng]

Gents,

Since I'm working with the same problems above, would someone please guide me through my code below, since I got an error to process it!!

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim v As Double ' fluid velocity
Dim Qv as integer = textbox1.text ' volumertric flow rate
Dim D2 as integer = textbox2.text
v = (4 * Qv) / (Math.PI * D2 ^ 2)
v = CDbl(TextBox9.Text)
End sub

[ChemEng]

Click this button:

thanks Zach

[jemidiah]

I think you at least want "v = CDbl(TextBox9.Text)" to be "TextBox9.Text = Val(v)". Otherwise the line above it does nothing.

[Pradeep1210]

Gents,

Since I'm working with the same problems above, would someone please guide me through my code below, since I got an error to process it!!

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim v As Double ' fluid velocity
Dim Qv as integer = textbox1.text ' volumertric flow rate
Dim D2 as integer = textbox2.text
v = (4 * Qv) / (Math.PI * D2 ^ 2)
v = CDbl(TextBox9.Text)
End sub

I think you better get familiar with different datatypes before you continue further with number manipulation. So in the above code you would be able to find the problem yourself.

Integers are numbers without any floating points. If you assign a decimal value to any datatype which can handle only integers (e.g. byte,short,integer,long) the decimal point will be stripped off; or worse cause an error. So if you want decimals to be considered, you must use one of those datatypes that can handle floating points. (e.g. single, double, decimal, currency etc.)

[ChemEng]

I think you at least want "v = CDbl(TextBox9.Text)" to be "TextBox9.Text = Val(v)". Otherwise the line above it does nothing.

Many thanks Jemidiah and your code worked well.

[ChemEng]

I think you better get familiar with different datatypes before you continue further with number manipulation. So in the above code you would be able to find the problem yourself.

Integers are numbers without any floating points. If you assign a decimal value to any datatype which can handle only integers (e.g. byte,short,integer,long) the decimal point will be stripped off; or worse cause an error. So if you want decimals to be considered, you must use one of those datatypes that can handle floating points. (e.g. single, double, decimal, currency etc.)

I appreciate your answer and I'm trying to understand the table by putting more examples and excersies to figure out the difference between each data type.

Load of cheers

[ChemEng]

Good evening..

As I went through the difference between each data type, I got a short code but I got it wrong somewhere in the declarations.

The code is below and please please I need your support here to run it :

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim Qv As Double
Dim Ao, A1 As Double
Dim D1 As Integer = TextBox1.Text

Dim D2 As Integer = TextBox2.Text
Ao = (Math.PI * D2 ^ 2) / 4
TextBox3.Text = Val(Ao) ' area of the orifice

A1 = (Math.PI * D1 ^ 2) / 4
TextBox4.Text = Val(A1) ' area of the pipe
Dim P1 As Integer = TextBox5.Text
Dim P2 As Integer = TextBox6.Text
Dim CD As Double = TextBox7.Text
Dim rho As Integer = TextBox8.Text
Qv = ((CD * Ao) / (Math.Sqrt(1 - (Ao / A1) ^ 2))) * Math.Sqrt((2 * (P1 - P2)) / (rho))
TextBox9.Text = Val(Qv)

End Sub


loads of cheers

[Pradeep1210]

Good evening..

As I went through the difference between each data type, I got a short code but I got it wrong somewhere in the declarations.

The code is below and please please I need your support here to run it :

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim Qv As Double
Dim Ao, A1 As Double
Dim D1 As Integer = TextBox1.Text

Dim D2 As Integer = TextBox2.Text
Ao = (Math.PI * D2 ^ 2) / 4
TextBox3.Text = Val(Ao) ' area of the orifice

A1 = (Math.PI * D1 ^ 2) / 4
TextBox4.Text = Val(A1) ' area of the pipe
Dim P1 As Integer = TextBox5.Text
Dim P2 As Integer = TextBox6.Text
Dim CD As Double = TextBox7.Text
Dim rho As Integer = TextBox8.Text
Qv = ((CD * Ao) / (Math.Sqrt(1 - (Ao / A1) ^ 2))) * Math.Sqrt((2 * (P1 - P2)) / (rho))
TextBox9.Text = Val(Qv)

End Sub


loads of cheers

Have a look at one of those variables that you declared INTEGER that might be causing the problem. To be on the safe side, you could declare all of them as DOUBLE.

[ChemEng]

Have a look at one of those variables that you declared INTEGER that might be causing the problem. To be on the safe side, you could declare all of them as DOUBLE.

That is true Pradeep, I found the problem and it looks working now,

many thanks again and again

[ChemEng]

Pradeep, Jemidiah and other experts;

I can say I'm almost in the finishings to end up my VB work, but I've the following code to be viewed and corrected please.
The code shall converts the textbox value according to the unit selected from the combobox. Example, if I enter 0.2 in the text box and put m as meter the value shall stay the same since m is the SI unit for length. Whereas if I change the unit to cm or mm from the combobox the value of 0.2 shall be converted into cm or mm according to the combobox unit selected, and visa versa if I put the value in cm or mm and want to change it to m then I just need to select the unit from the combobox.
I put the code but when I've tried to return it to m I failed as it keep converting, which gives wrong figures.

The code is

Public Class Form1
Dim unit_d1 As Single = 1 'multiple input in D1 by this value to get into SI units
Dim unit_d2 As Single = 1
Dim DI As Double 'pipe internal dia

Private Sub ComboBox1_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ComboBox1.SelectedIndexChanged
Dim unit As String
unit = ComboBox1.Text ' get current value from combo box

If unit = "m" Then
DI = DI * 1.0
ElseIf unit = "cm" Then
DI = DI * 0.01
ElseIf unit = "mm" Then
DI = DI * 0.001
Else
If TextBox1.Text = " " Then
MsgBox(" please enter a valid ID value")

End If
End If
TextBox1.Text = DI
End Sub

Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
ComboBox1.Items.Add("m")
ComboBox1.Items.Add("cm")
ComboBox1.Items.Add("mm")
ComboBox1.SelectedIndex = 0

TextBox1.Text = "0.2"
DI = CSng(TextBox1.Text)
End Sub

Private Sub TextBox1_Leave(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles TextBox1.Leave
'Dim DI As Double 'Commented by Mr.Z !!

If (TextBox1.Text.Length > 0) Then ' dont check empty textbox
DI = CSng(TextBox1.Text) ' only apply the unit multiplier when the calc button is pressed.
If (DI > 0.4) Or (DI <= 0.1) Then
MsgBox(" Pipe ID to be from >0.1m to 0.4m ")
End If
End If
End Sub
End Class

Loads of cheers

[Pradeep1210]

You are not storing the value of textbox anywhere before changing it. So whenever combobox value changes, only the latest value is assumed to be in metres. You should store the actual metre value somewhere before applying the change.
Also, the Units and the Multiplier go side by side. So instead of calculating the multiplier in the combobox change event, you could keep it with the item itself. Since the combobox Items is a collection of objects, you can store both the things (maybe more properties if you want) in the Items collection as a Class or Structure.


PS: Please put your code in [CODE] or [HIGHLIGHT] tags to make it more readable.


[EDIT] Code removed and posted modified code in next post [/EDIT]


Pradeep

[Pradeep1210]

I think this is what you need:

Public Class Form1
    Dim DI As Double 'pipe internal dia
 
    Private Sub ComboBox1_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ComboBox1.SelectedIndexChanged
        TextBox1.Text = DI * ComboBox1.SelectedItem.Multiplier
    End Sub
 
    Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        ComboBox1.Items.Add(New SIUnit("m", 1))
        ComboBox1.Items.Add(New SIUnit("cm", 100))
        ComboBox1.Items.Add(New SIUnit("mm", 1000))
        ComboBox1.DropDownStyle = ComboBoxStyle.DropDownList
        ComboBox1.SelectedIndex = 0
 
        TextBox1.Text = "0.2"
        DI = CDbl(TextBox1.Text)
    End Sub
 
    Private Sub TextBox1_Leave(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles TextBox1.Leave
        If (TextBox1.Text.Length > 0) Then ' dont check empty textbox
            If (DI > 0.4) Or (DI <= 0.1) Then
                MsgBox(" Pipe DI to be from >0.1m to 0.4m ")
            End If
        End If
    End Sub
 
    Private Sub TextBox1_KeyUp(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyEventArgs) Handles TextBox1.KeyUp
        DI = Val(TextBox1.Text) / ComboBox1.SelectedItem.Multiplier
    End Sub
 
End Class
 
Public Structure SIUnit
    Public Unit As String
    Public Multiplier As Single
    Public Sub New(ByVal unit As String, ByVal multiplier As Single)
        Me.Unit = unit
        Me.Multiplier = multiplier
    End Sub
    Public Overrides Function ToString() As String
        Return Me.Unit
    End Function
End Structure

[ChemEng]

Happy New Year every1 and wish all our dreams turn true. Wish the peace to spread over the world. Wish all the people live in an equity and prosperity .

Thanks very much Pradeep for your time and valuable comments and I highly appreciate your support and concern. Thanks for Jemidiah as well. Many thanks for everyone tried to put some effort in this issue.

[ChemEng]

Hi again

I have a combobox with drop down list say water, Oil, air and Gas.
I have a volumetric flow rate formula is used to calculate the flow when the combobox selection is water, oil and air. Whereas for Gas I have different formula. Now, I need to switch the volumetric flow rate calculation according to the combobox selection.

Here is the code (refering to above help from Pradeep and Jemidiah)


Qv = ((CD * A2) / (Math.Sqrt(1 - (A2 / A1) ^ 2))) * Math.Sqrt((2 * (P1 - P2)) / (rho)) ' formula cited from Perry chapter 8-48 Process Control
TextBox12.Text = Val(Qv) 'Calculated volumetric flow rate based on selected orifice size
If ComboBox6.SelectedIndex = 3 Then ' selection 3 refers to Hydrocarbon Gas
Dim expcoeff, Qv As Double ' expcoeff is e or expansion coefficient for gas

Qv = ((CD * expcoeff * (Math.Sqrt(1 / (1 - (D2 / D1) ^ 4))) * ((Math.PI * D2 ^ 2) / 4) * (Math.Sqrt(2 * (P1 - P2)) / (rho))))
TextBox12.Text = Val(Qv)
expcoeff = 1 - (0.41 + 0.35 * (D2 / D1) ^ 4) * ((P1 - P2) / (1.4 * P1)) ' 1.4 refers to k which is a isentropic coefficient for gas
TextBox16.Text = Val(expcoeff)
End If

When I put this code and choise gas from the dropdown list of the combobox the Qv value in the textbox will turn to 0 !!!1

[ChemEng]

After many attempts, I've solved the above problem...

Cheers.