Rationalising factor for Pi

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Originally posted by Guv
Oddly bit of related information.

e^i*Pi = -1

Where i is SquareRoot(-1), and e is 2.71828...

IMHO, that's not at all odd..

It's just the exponential form of the complex number -1+i*0 (or)

1*[Cos(pi)+iSin(pi)] (or) 1*[Cos(180^o)+i Sin(180^o)]

...
r*[Cos(theta)+iSin(theta)] can be expressed as r*e^(i*theta)

Where r =Sqr(a^2+b^2) is the modulus of complex number a+ib
and theta is the principal argument of the complex number such that
r*cos(theta) = a and r*sin(theta)=b
....

On the basis of the above, I believe that your search for a so called rationalizing factor is doomed.

Yes.. I have to agree with this.