Producing a random number from a range

[MountainDew7]

I'm trying to make a random number from -100 to 100 in VB6, but all that's coming out is negative numbers. This is what I have:

Randomize
x = int(rnd * 100) - 100

Any ideas?

[si_the_geek]

The Rnd function returns a number from 0 to just under 1, so int(rnd * 100) will give you a number from 0 to 99, and subtracting 100 from that will give you -100 to -1

You should be changing *100 to something else.

[MountainDew7]

Ah, so would this be it?

int(rnd * 200) - 100

[si_the_geek]

That will return (0 to 199) - 100 , which is -100 to 99

[Code Doc]

Ah, so would this be it?

int(rnd * 200) - 100

Not quite, but this does it:

Int(Rnd * 201) - 100

That will include random numbers ranging from -100 to +100 inclusive.

[anhn]

The formula is: x = Int(Rnd * (Hi - Lo + 1)) + Lo
Here you have: Lo = -100, Hi = 100
So: x = Int(Rnd * (100 - (-100) + 1)) + (-100)
or: x = Int(Rnd * 201) - 100

[hendersondayton]

what if u just wanted a small number like 1 to 6?

[hendersondayton]

it would just be Int(Rnd * 7)

[Code Doc]

it would just be Int(Rnd * 7)

No. Please read AnHn's post showing the formula. For a range from 1 to 6 inclusive, Lo = 1, Hi = 6. Got it?

[anhn]

what if u just wanted a small number like 1 to 6?

it would just be Int(Rnd * 7)

Int(Rnd * 7) give you a random integer between 0 to 6 inclusive.

To get a random number between 1 and 6, use the formula in my post#6 above:
x = Int(Rnd * (6 - 1) + 1) +1
or
x = Int(Rnd * 6) + 1