Macromedia Fireworks, image fading, graphics gurus help needed :-)
Hey guys - just a graphics problem.
I want some way of fading an image into the background using Fireworks 4... for example, I know how to do gradient fills and all, but I want to fade an image that's already there (transparent background) so it fades nicely into the background... is it possible? If not, does anyone know of a prog that does it?
You should be able to do it in Fireworks with no problem.. Though a quick question... are you trying to fade out over time? If you are don't do it in Fireworks... Use either Flash or ImageReady...
Use
writing software in C++ is like driving rivets into steel beam with a toothpick.
writing haskell makes your life easier:
reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
Use
writing software in C++ is like driving rivets into steel beam with a toothpick.
writing haskell makes your life easier:
reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.
Yes in Fireworks click the object you want to fade.
Make sure you have the object toolbar open.
In the top left corner of the object toolbar is a chequered rectangle. Next to that is 100 in a drop down box. Change the value in this to change the opacity of the object.
Alex
ASP, SQL, VB6, Java Script and dubious guitar playing skills.
i'm sorry about scaring you with 31. Dunno about fireworks but can you use alpha channels?
Use
writing software in C++ is like driving rivets into steel beam with a toothpick.
writing haskell makes your life easier:
reverse (p (6*9)) where p x|x==0=""|True=chr (48+z): p y where (y,z)=divMod x 13
To throw away OOP for low level languages is myopia, to keep OOP is hyperopia. To throw away OOP for a high level language is insight.