Textbox line by line

[BULK]

Hi
Maybe I'm just to tired to see what I'm missing, but I could need some help with this.
I have 2 textboxes, one with hex data and one which I convert to ASCII. The first textbox is sized to fit 16 chr, this will be equal to 8 Ascii. I wan't my code to convert line by line. Which means that max chr in a line for textbox2 should be 8. Maybe I should use a StreamWriter, instead of my code?

Public Class Form1
    Private Sub Button2_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click

        Dim hex As String = TextBox1.Text
        Dim hexNumber As Integer
        Dim i As Integer
        For i = 0 To hex.Length - 1 Step 2
            hexNumber = Convert.ToInt32(TextBox1.Text.Substring(i, 2), 16)

            For Each line As String In TextBox1.Lines
                TextBox2.AppendText(Chr(hexNumber & vbCrLf))
            Next
        Next
    End Sub

End Class

[Teme64]

Here you go

Private Sub Button2_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click

    Dim hexNumber As Integer
    Dim i As Integer

    For Each line As String In TextBox1.Lines
      For i = 0 To line.Length - 1 Step 2
        hexNumber = Convert.ToInt32(line.Substring(i, 2), 16)
        TextBox2.AppendText(Chr(hexNumber))
      Next i
      TextBox2.AppendText(vbCrLf)
    Next

End Sub

Teme64 @ windevblog.blogspot.com

[BULK]

Hi
Thank's
Well the outcome is about the same as i had, yours will though goto next line everytime the button is clicked. But it will fill the whole Textbox2 line, even if Textbox 1 line is shorter. Textbox1 line1 should be equal to Textbox2 line1, but converted to ASCII.

[Teme64]

Maybe I missed something. TextBox1 contains, lets say:
64646464
65656565
that's two lines with 4 hex values (8 characters). The code converts it to:
dddd
eeee
which is 4 ascii chars. You try to do that, don't you?

But it will fill the whole Textbox2 line, even if Textbox 1 line is shorter

Don't understand what you mean by that.

Does your TextBox1 contain some binary data to be converted to ascii?

Teme64 @ windevblog.blogspot.com

[BULK]

Hi
Well, sort of. Here's an example:

45 00 01 35 24 DC 00 00 80 11 90 27 C0 A8 01 66 
C0 A8 01 FE FA A1 56 F2 01 21 A3 7B 64 31 3A 72 
64 32 3A 69 64 32 30 3A 1B 4F 71 18 55 CC E1 B8 
E8 6B 95 96 18 A0 66 91 B8 F9 5C 37 35 3A 6E 6F 
64 65 73 32 30 38 3A 1B 54 D9 EE 37 75 5D ED D6 
00 C4 DF C7 1B ED 3C 6E 26 03 8A 4D CA 25 7B 4A 
3D 1B 54 AA 77 5F 9B BF 17 6E 37 73 99 7D D6 AB 
37 B5 AF A0 1B C0 A8 01 FE 49 CA 1B 53 B0 12 25 
92 6F 71 43 B5 E5 9C CD 4A EE 8A 53 6B 0F B6 55 
31 FB DA 3E AE 1B 53 46 48 9C C6 4A 6A F6 BA A1 
04 87 27 38 E3 3A 5C F3 EE 7D E8 89 58 56 E7 1B 
53 6B E7 7B AB 01 71 3E 1E 3E 97 94 90 EA D8 94 
2A 76 82 5B 43 0D 33 62 2B 1B 52 3F 46 19 4D 43 
FE B9 64 B6 2B A2 95 EC 18 37 31 FF 8D 43 B7 88

If you copy and past this into textbox1 then textbox2 will have 6 lines, instead of 14.
Oh, and I'm using:

 TextBox1.Text = Replace(TextBox1.Text, Chr(32), String.Empty) 'Space

Just for the blanks.

[kleinma]

the line wraps in textboxes are dictated by 2 different things, and they are very different in actual functionality.

A line in a textbox of course only wraps when the textbox is multiline.

However a line wraps in a multiline textbox when

1) a newline character (crlf) is appended to the text, as is the case when you hit enter to go to a new line
2) your current line takes up more than the visible area of the textbox, and the wordwrap property is set to true (which is the default).

So for what you are trying to do, you really want to separate your lines by actual newline characters. You could use environment.newline to get that via code.

Also, if you do it that way, you can access the textbox's lines property to access each individual line. This doesn't work if you just have the lines wrapped because of the size of your textbox and you have wordwrap on, because its still technically just 1 long single line string being displayed over multiple lines visually.

So to iterate over every line when you do it as I mentioned, is as simple as this:

        For Each S As String In TextBox1.Lines
               'do stuff with S
        Next

[BULK]

Thank's for reply

Well using this will only convert the first hex value:

  Dim hexNumber As Integer
        Dim i As Integer
        For Each S As String In TextBox1.Lines
            hexNumber = Convert.ToInt32(TextBox1.Text.Substring(i, 2), 16)
            TextBox2.AppendText(Chr(hexNumber & vbCrLf))
        Next

[Teme64]

Use my previous reply:

For Each line As String In TextBox1.Lines
    For i = 0 To line.Length - 1 Step 2
      hexNumber = Convert.ToInt32(line.Substring(i, 2), 16)
      TextBox2.AppendText(Chr(hexNumber))
    Next i
    TextBox2.AppendText(vbCrLf)
 Next

It loops
1) lines in TextBox1 (multiline=True)
2) for each line, it loops each two character (=1 hex char) pair
and you may substitute TextBox2.AppendText(vbCrLf) with TextBox2.AppendText(Environment.Newline) which kleinma stated. It's preferred way over vbCrLf in .NET.

[dbasnett]

i had to try.

        Dim HexVals() As Byte = New Byte() {&H45, &H0, &H1, &H35, &H24, &HDC, &H0, _
                                            &H0, &H80, &H11, &H90, &H27, &HC0, &HA8, _
                                            &H1, &H66, &HC0, &HA8, &H1, &HFE, &HFA, _
                                            &HA1, &H56, &HF2, &H1, &H21, &HA3, &H7B, _
                                            &H64, &H31, &H3A, &H72, &H64, &H32, &H3A, _
                                            &H69, &H64, &H32, &H30, &H3A, &H1B, &H4F, _
                                            &H71, &H18, &H55, &HCC, &HE1, &HB8, &HE8, _
                                            &H6B, &H95, &H96, &H18, &HA0, &H66, &H91, _
                                            &HB8, &HF9, &H5C, &H37, &H35, &H3A, &H6E, _
                                            &H6F, &H64, &H65, &H73, &H32, &H30, &H38, _
                                            &H3A, &H1B, &H54, &HD9, &HEE, &H37, &H75, _
                                            &H5D, &HED, &HD6, &H0, &HC4, &HDF, &HC7, _
                                            &H1B, &HED, &H3C, &H6E, &H26, &H3, &H8A, _
                                            &H4D, &HCA, &H25, &H7B, &H4A, &H3D, &H1B, _
                                            &H54, &HAA, &H77, &H5F, &H9B, &HBF, &H17, _
                                            &H6E, &H37, &H73, &H99, &H7D, &HD6, &HAB, _
                                            &H37, &HB5, &HAF, &HA0, &H1B, &HC0, &HA8, _
                                            &H1, &HFE, &H49, &HCA, &H1B, &H53, &HB0, _
                                            &H12, &H25, &H92, &H6F, &H71, &H43, &HB5, _
                                            &HE5, &H9C, &HCD, &H4A, &HEE, &H8A, &H53, _
                                            &H6B, &HF, &HB6, &H55, &H31, &HFB, &HDA, _
                                            &H3E, &HAE, &H1B, &H53, &H46, &H48, &H9C, _
                                            &HC6, &H4A, &H6A, &HF6, &HBA, &HA1, &H4, _
                                            &H87, &H27, &H38, &HE3, &H3A, &H5C, &HF3, _
                                            &HEE, &H7D, &HE8, &H89, &H58, &H56, &HE7, _
                                            &H1B, &H53, &H6B, &HE7, &H7B, &HAB, &H1, _
                                            &H71, &H3E, &H1E, &H3E, &H97, &H94, &H90, _
                                            &HEA, &HD8, &H94, &H2A, &H76, &H82, &H5B, _
                                            &H43, &HD, &H33, &H62, &H2B, &H1B, &H52, _
                                            &H3F, &H46, &H19, &H4D, &H43, &HFE, &HB9, _
                                            &H64, &HB6, &H2B, &HA2, &H95, &HEC, &H18, _
                                            &H37, &H31, &HFF, &H8D, &H43, &HB7, &H88}
        Dim strr As Char() = New Char(HexVals.Length - 1) {}
        strr = System.Text.Encoding.GetEncoding("Windows-1252").GetChars(HexVals)
        Dim ts As String
        ts = New String(strr, 0, strr.Length - 1)
        Dim TBh As New TextBox, TBa As New TextBox
        Const perLnH As Integer = 16
        Dim ctHch As Integer = 0
        For z As Integer = 0 To ts.Length - 1
            TBh.Text &= HexVals(z).ToString("X").PadLeft(2, "0"c) & " "
            TBa.Text &= ts.Substring(z, 1) & " "
            ctHch += 1
            If ctHch >= perLnH Then
                TBh.Text &= Environment.NewLine
                TBa.Text &= Environment.NewLine
                ctHch = 0
            End If
        Next

[Teme64]

One more modification (remove spaces):

Dim hex As String = TextBox1.Text
Dim hexNumber As Integer
Dim i As Integer

For Each line As String In TextBox1.Lines
  line = Replace(line, Chr(32), String.Empty)
  For i = 0 To line.Length - 1 Step 2
    hexNumber = Convert.ToInt32(line.Substring(i, 2), 16)
    TextBox2.AppendText(Chr(hexNumber))
  Next i
  TextBox2.AppendText(vbCrLf)
Next

and this code works. But the point is, printable ASCII characters are in the range 32-127, and some of your sample hex values are outside of this range. The code above should check if the hex value is not a printable ASCII it outputs, lets say a dot (.) character. Like this:

Dim hex As String = TextBox1.Text
Dim hexNumber As Integer
Dim i As Integer

For Each line As String In TextBox1.Lines
  line = Replace(line, Chr(32), String.Empty)
  For i = 0 To line.Length - 1 Step 2
    hexNumber = Convert.ToInt32(line.Substring(i, 2), 16)
    If hexNumber >= 32 AndAlso hexNumber <= 127 Then
      TextBox2.AppendText(Chr(hexNumber))
    Else
      TextBox2.AppendText(".")
    End If
  Next i
  TextBox2.AppendText(vbCrLf)
Next

If you copy and past this into textbox1 then textbox2 will have 6 lines, instead of 14.

I copy pasted those 14 lines in to my test code and got out 14 lines. Check your line break characters. Some lines may have vbCr or vbLf instead of vbCrLf. If the original content comes from a file this may well be the case.

Teme @ windevblog.blogspot.com

[BULK]

Well your code work's. But let's take an other example, now I'm back to 6 lines??

45 00 05 AC 7F 8C 40 00 2C 06 7D E9 3F EC 49 DC 
C0 A8 01 66 00 50 08 70 F5 B7 16 86 B7 FF C7 77 
50 10 1F DA 68 E1 00 00 48 54 54 50 2F 31 2E 31 
20 32 30 30 20 4F 4B 0D 0A 44 61 74 65 3A 20 53 
75 6E 2C 20 32 38 20 53 65 70 20 32 30 30 38 20 
32 30 3A 32 30 3A 32 30 20 47 4D 54 0D 0A 53 65 
72 76 65 72 3A 20 41 70 61 63 68 65 0D 0A 45 78 
70 69 72 65 73 3A 20 30 0D 0A 43 61 63 68 65 2D 
43 6F 6E 74 72 6F 6C 3A 20 70 72 69 76 61 74 65 
2C 20 70 6F 73 74 2D 63 68 65 63 6B 3D 30 2C 20 
70 72 65 2D 63 68 65 63 6B 3D 30 2C 20 6D 61 78 
2D 61 67 65 3D 30 0D 0A 50 72 61 67 6D 61 3A 20 
6E 6F 2D 63 61 63 68 65 0D 0A 4B 65 65 70 2D 41 
6C 69 76 65 3A 20 74 69 6D 65 6F 75 74 3D 35 2C

How come?

[Teme64]

From that data, I get:

E....@.,.}.?.I.
...f.P.p.......w
P...h...HTTP/1.1
 200 OK..Date: S
un, 28 Sep 2008 
20:20:20 GMT..Se
rver: Apache..Ex
pires: 0..Cache-
Control: private
, post-check=0, 
pre-check=0, max
-age=0..Pragma: 
no-cache..Keep-A
live: timeout=5,

when non-printable ASCII chars were replaced with dot. And that's 14 lines.

Are you sure your TextBox2 is a) MultiLine=True and b) ScrollBars=Vertical so that you can see all the lines?

Another point, your hex sample contains six 0D 0A values (=CR+LF) which would explain why you got six lines. So, how do you fill TextBox1 in the first place? I got 14 lines because I copy pasted text from your post, not original binary data. Do you fill TextBox1:

Dim ByteArr() As Byte
Dim i As Integer
For i = 0 To ByteArr.Length - 1
  TextBox1.Text = TextBox1.Text & String.Format("{0:X2} ", ByteArr(i))
Next i

or with any similar code? Or do you "dump" binary data straight into TextBox1? (Ok, I admit I don't know how you could do that )

Teme @ windevblog.blogspot.com