How do you prove this: Code: (a^x)' = a^x * ln(a) I've been banging my head about it, help
(a^x)' = a^x * ln(a)
y = a^x ln(y) = x*ln(a) d[ ln(y) ]/dx = ln(a) (1/y)*dy/dx = ln(a) dy/dx = ln(a)*y dy/dx = ln(a)*a^x
Live long & prosper. The Dinosaur from prehistoric era prior to computers. Eschew obfuscation! If a billion people believe a foolish idea, it is still a foolish idea! VB.net 2010 Express 64Bit & 32Bit Windows 7 & Windows XP. I run 4 operating systems on a single PC.
WOO! Thanks a lot, why didn't I think of taking the natural logarithm of both sides
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