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Dec 19th, 2007, 11:23 AM
#1
Thread Starter
New Member
[Solved] how to find the equation of a curve, given: 2 gradients & 1 x,y coordinate
Given:
when x=c, gradient1 = -2 when x=b, gradient2 = 0 and y=0 x=[0..2]
How would I find the equation for a concave curve?
(note: I have pre-calc experience, but only cursory calculus knowledge. Any help would be greatly appreciated.)
Last edited by viknord; Dec 19th, 2007 at 10:05 PM.
Reason: clarified title
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Dec 19th, 2007, 08:45 PM
#2
Fanatic Member
Re: how to find the equation of a curve, given: 2 gradients & 1 x,y coordinate
Welcome to the forums!
There are probably infinitely many functions that could satisify the 3 conditions. However, if you want to limit yourself to the lowest degree polynomial, a quadratic should do:
y = ax2 + bx + c
y' = 2ax + b
where a, b, c are unknown. The 2nd equation is the gradient (1st derivative). You need 3 equations, which can be written to satisfy the constraints:
y1 = ax12 + bx1 + c
y2' = 2ax2 + b
y3' = 2ax3 + b
This is a set of 3 simultaneous linear equations that can be solved for a, b, c by Gauss elimination. Actually the 2nd two equations only involve a & b and can be easily solved by substitution. Once a & b are known, c can be solved in the 1st equation.
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Dec 19th, 2007, 10:04 PM
#3
Thread Starter
New Member
Re: how to find the equation of a curve, given: 2 gradients & 1 x,y coordinate
Thanks for the help VBAhack. I was able to figure it out from there.
a = 1
b = -4
c = 4
y = x^2 - 4x + 4
How did you determine the equation/curve would be a quadratic? I was trying all kinds of formulas (randomly) such as radioactive decay, but I wasn't sure how to tie-in the gradients (derivatives).
Thanks again for replying. Now I can move on to figuring the area below the curve and then the volume as the curve is rotated 360 degrees.
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Dec 20th, 2007, 09:48 PM
#4
Fanatic Member
Re: how to find the equation of a curve, given: 2 gradients & 1 x,y coordinate
 Originally Posted by viknord
How did you determine the equation/curve would be a quadratic?
Educated guess. Polynomials are often a good place to start - they are simple. Also, since you had 3 pieces of information, a function with 3 parameters is the obvious thing to try first - thus, a polynomial with 3 parameters.
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Dec 21st, 2007, 12:39 AM
#5
Thread Starter
New Member
Re: [Solved] how to find the equation of a curve, given: 2 gradients & 1 x,y coordinate
Btw, would you recommend any good Calculus books? Self/home-study type books. I've been reading "Calculus for Cats" by Amdahl and Loats (which helps conceptually) and "Calculus: An Intuitive and Physical Approach" by Kline (just started this one).
Thanks again.
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Dec 21st, 2007, 12:23 PM
#6
Fanatic Member
Re: [Solved] how to find the equation of a curve, given: 2 gradients & 1 x,y coordinate
 Originally Posted by viknord
would you recommend any good Calculus books?
Nope, but you might try here:
http://www.physicsforums.com/forumdisplay.php?f=21
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