[2005] open file dialog problem

[xorcst]

Dim fileStream As System.IO.FileStream = Nothing
try that

[Icyculyr]

try this

Private Sub button1_Click(ByVal sender As Object, ByVal e As System.EventArgs)
    Dim ofd As New OpenFileDialog()

    Dim MyValue As String = ""
    ofd.InitialDirectory = "c:\"
    ofd.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*"
    
    If ofd.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
        Using sr As New StreamReader(ofd.FileName)
            MyValue = sr.ReadToEnd()
        End Using
    End If
End Sub

That should work, and if the file is not found
use ofd.CheckFilePath, or a property with a similar name which checks the file exists...