Parse URL

[RobDog888]

I need a url parse function for php 4.1+ I found the parse_url function but I need to parse the actual url the page is on and not just a constant string value or such.

Im trying to figure out if the page is the home page (index.php) because if its not then I need to do some conditional coding.

Thnaks

[penagate]

parse_url($_SERVER['REQUEST_URI']);

[RobDog888]

Thanks, and so with the actual url I can use some function to split the paths?

[penagate]

parse_url will return an associative array containing the components of the URL. If you want, you can instead use basename() to get the file name of the URL or dirname() to get the directory.

If you want to check whether the current script is index.php, as opposed to the current URL, you can simply use:

if (basename(__FILE__) == 'index.php') {
  // ...
} 

[RobDog888]

Well the deal is that there may be multiple file names of the same names but different complete paths. So just comparing the file name is no good.

Seems like a combination of getting the basename and if its a root directory location would do the trick.

[RobDog888]

So this will retrieve the current url into the variable. Then parse it and check the directory levels to make sure its at the root.

$url = parse_url($_SERVER['REQUEST_URI']);
//Some kind of splitting to an array and then counting the ubound. 
//Then match the file name?
arrUrl$ = somesplitfunction($url, '/');
if (basename(arrUrl[2]) == 'index.php') { 
  // ... 
} 

[RobDog888]

I think this is it?

$url = parse_url($_SERVER['REQUEST_URI']); 
//Some kind of splitting to an array and then counting the ubound.  
arrUrl$ = explode('/', $url); 
//Check if its the root level
if (count(arrUrl$) == 3) {
  //Then match the file name? 
  if (basename(arrUrl[3]) == 'index.php') {  
    // 
  }
} 

[dclamp]

you need to have the dollar sign in front of your strings:

$url = parse_url($_SERVER['REQUEST_URI']); 
//Some kind of splitting to an array and then counting the ubound.  
$arrUrl = explode('/', $url); 
//Check if its the root level
if (count($arrUrl) == 3) {
  //Then match the file name? 
  if (basename($arrUrl[3]) == 'index.php') {  
    // 
  }
} 

[RobDog888]

True, thanks. Just me being tired last night/morning and also being dyslexic.