How to use ReDim in vb.net+ Sourabh Das

[sd1978]

Hi,
This code is in vb6. How do I use the redim keyword in vb.net.

Public Sub FillVendor()
On Error GoTo err
I = 0
Set rs = New ADODB.Recordset
rs.Open "select * from tbl_vendor where isdeleted=0", cn, 1, 1
ReDim arrVendorId(rs.RecordCount)
While Not rs.EOF = True
    cmbVendor.AddItem rs("Vendor_name")
    arrVendorId(I) = rs("Vendor_Id")
    I = I + 1
    rs.MoveNext
Wend
Exit Sub
err:
    MsgBox err.Number & "- " & err.Description, vbInformation, err.Source
    Call I_Process_Errors("frmItem:FillVendor", err.Number, err.Description, err.Source)
End Sub

Regards,

[jmcilhinney]

ReDim does in VB.NET exactly what it did in VB6. If you want to know how to use any key word, statement, property or method then just look it up in the MSDN library.

http://search.msdn.microsoft.com/sea...=00&lang=en-us

[talkro]

dim string() as string
 
dim counter = 6 
redim string(counter)
 
for i as integer = 0 to 6
  string(i) = "whatever"
next i

[robertx]

Note that ReDim will reset any existing elements of the array to the default values. If you wish to keep the existing values then use the Preserve keyword.

eg. ReDim Preserve sArray(20)

[sd1978]

Hi,
I am unable to understand it.
Please help me giving a small piece of code.
Its urgent.
Regards,

[sd1978]

Hi TalkRo,
Why did you take counter as 6.
actually this count should be the number of rows present in the table if i am not wrong..
so instead of that should i write the count of records and if yes then
what will be the change in the for loop.

[robertx]

'declare and allocate 2 elements to a string array 
Dim sArray(1) As String

'assign values to the 2 elements
sArray(0) = "yes"
sArray(1) = "no"

'redimension the array allocating a third element
ReDim Preserve sArray(2)

'assign a value to the third elements
sArray(2) = "hello"

If you weren't to use the Preserve keyword above, the values "yes" and "no" would be lost and replaced with Nothing.

[talkro]

dim i as integer = 0
dim str() as string
dim counter as integer = ds.tables("yourTableName").Rows.count
redim str(counter)
for each row as datarow in ds.tables("yourTableName").Rows
  string(i) = row("ID").toString()
  i += 1
next row