[RESOLVED] rows display picture

[vbbit]

I have this image source <img src=....> I want it to be displayed in a table that has as many rows as the picture in the database increases but limitted to five rows.

For exmaple, if the table has one picture,

then

<table>
<tr><td><img src....>
</td></tr></table>

But if the database has 2 pictures, then another row is automatically added to the page, that would be second row to store second picture.

[asterix299]

Well I don't completely understand what you're trying to do but if it's what I think, then use a loop to display the pictures depending on how many there are (up to five):

$numPics = count($pics);
if ($numPics > 5) {
  for ($i = 0; $i <= 4; $i++) {
    echo "<tr><td><img src=\"$pics[$i]\"></td></tr>";
  }
} else {
  for ($i = 0; $i <= $numPics - 1; $i++) {
    echo "<tr><td><img src=\"$pics[$i]\"></td></tr>";
  }
} 

Just put the path to the pictures into the $pics array in any way you see fit, whether randomly or whatever, and have it display up to five of them.

[vbbit]

Not quite what I wanted. See I want a table that can list many photos in "rows" but each row can consist of only five photos. Which means, the first rows has five pictures, second row has five pictures and so on. ...

[kows]

a bit messy. you get the idea, though.

<?php
  $pictures = array("picture1", "picture2", "picture3", "picture4", "picture5", "picture6", "picture7");
  $ii = 0; //index for the row
  $cols = 5; //number of columns in each row
  $ncol = true; //whether or not to make a new column
  for($i = 0; $i <= count($pictures) - 1; $i++){
    $ii++;

    //end a row?
    if($ii > $cols){
      $ii = 0; //reset row index
      echo '</tr>' . "\n";
      $ncol = true;
    }

    //start a new row?
    if($ncol == true){
      $ncol = false;
      echo '<tr>' . "\n";
    }

    //display image
    echo '  <td><img src="' . $pictures[$i] . '" /></td>' . "\n";

    //is the table finished?
    if($i == count($pictures) - 1){
      //finish filling the row if we need to
      if($ii < $cols){
        for($j = $ii; $j < $cols - 1; $j++){
          echo '  <td>&nbsp;</td>' . "\n";
        }
      }
      echo '</tr>' . "\n";
    }
  }
?>

[vbbit]

Kows, thank you for giving me the idea. I went ahead and wrote up my own code:

<?php
  $pictures = array("picture1", "picture2", "picture3", "picture4", "picture5", "picture6", "picture7", "picture8", "picture9", "picture10", "picture11");
  $ii = 0; //index for the row
  $cols =2; //number of columns in each row
  for($i = 0; $i <= count($pictures) - 1; $i++)
  {
      // increment row index
      $ii++;
      
      if ($i ==0)
      {
         echo "<table border=0>\n<tr>\n";

      }
      
       echo "<td>$pictures[$i]</td>\n";

      
      if ($ii >= $cols)
      {
         echo "</tr>\n<tr>\n";
         $ii=0; //reset the index row
      }
      
      if ($i==count($pictures)-1)
      {
         echo "</tr></table>";
      }
  }

?>