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Thread: [RESOLVED]ID number generator

  1. #1

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    Fanatic Member Mxjerrett's Avatar
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    Resolved [RESOLVED]ID number generator

    Well I am building an ID number generator. How can I loop through a string and find the ascii value of each character. Example

    String Mxjerrett
    Converted 77120106101114114101116116
    Last edited by Mxjerrett; May 11th, 2007 at 06:18 PM.

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  2. #2
    Fanatic Member r0ach's Avatar
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    Re: ID number generator

    Code:
    Dim i As Integer
    Dim strID As String
    Dim strName As String
    
      strName = "Mxjerrett"
      strID = ""
      For i = 1 to Len(strName)
        strID = strID & Asc(Mid(strName, i, 1))
      Next

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  3. #3
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    Re: ID number generator

    I think he wants to convert "77120106101114114101116116" back to "Mxjerrett"

    That code looks like it will do what he already did. But, not sure how you would convert that back without having some sort of seperator between each number that is a letter.

    Looking at the end of the converted string, how would you say "Convert 16, then 116" or "Convert 61, then 16"

    You could have it insert something between each converted letter, so it would be like.. "77.120.106...." but that would be easy to reverse (though not like what you have now will stump anyone )
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  4. #4
    Fanatic Member r0ach's Avatar
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    Re: ID number generator

    Well he said he's generating an ID number. He said he wanted to loop through a string and find the ascii value for each char.

    What I would have done with your suggested problem is this:

    Code:
    Dim i As Integer
    Dim strID As String
    Dim strName As String
    Dim strAscii As String
    
      strName = "Mxjerrett"
      strID = ""
      For i = 1 to Len(strName)
        strAscii = Asc(Mid(strName, i, 1))
        strID = strID & Len(strAscii) & strAscii
      Next
    The ID would be "27731203106310131143114310131163116"
    This will be easy to convert back to a name, but because the 3's look like delimiters it's still not perfect. From there I'd chop it into groups of 2 and convert it to 2 char hex (6 = 06, F = 0F) leaving "1B490C030A3F0A0D0B2B0B2B0A0D0B3F0B06". Simple, I know. And nowhere near foolproof. But easy to convert back to a name, and not obvious.

    Here's some quick code:
    Code:
    Dim i As Integer
    Dim strID As String
    Dim strTmp As String
    Dim strHex As String
    Dim strName As String
    Dim strAscii As String
    
       strName = "Mxjerrett"
       strID = ""
       For i = 1 To Len(strName)
          strAscii = Asc(Mid(strName, i, 1))
          strID = strID & Len(strAscii) & strAscii
       Next
       
       'strID = 27731203106310131143114310131163116
    
       strTmp = ""
       For i = 1 To Len(strID) Step 2
          strHex = Right("00" & Hex(Val(Mid(strID, i, 2))), 2)
          strTmp = strTmp & strHex
       Next
       'strTmp = 1B490C030A3F0A0D0B2B0B2B0A0D0B3F0B06

    r0ach™
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  5. #5

    Thread Starter
    Fanatic Member Mxjerrett's Avatar
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    Re: ID number generator

    Your code works perfectly, but now I need help deconverting it. I have the program putting - in between each character, but now I need to try to convert it back to characters. Ex:

    My ID: 77-88-74-69-82-82-69-84-84

    My Username (yes I know it is caps): MXJERRETT

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  6. #6

    Thread Starter
    Fanatic Member Mxjerrett's Avatar
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    Re: ID number generator

    Nevermind guys, I wrote my own code that seems to work 100% perfectly. Here is the code in case you guys wanted to know:

    Code:
    Dim strAscii, strID, strName As String
    
    strID = Replace(txtID, "-", "")
        For i = 1 To Len(strID) / 2
            strAscii = Chr(Right(Left(strID, i * 2), 2))
            strName = strName & strAscii
        Next
        txtName = strName

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