[RESOLVED] [2005] Get SeletedValues from ListBox with Multi-Select

[bmahler]

Ok, so I populate a listbox with a dataset like so

lbNucs.DataSource = ds.Tables(0)
lbNucs.DisplayMember = "Analyte"
lbnucs.ValueMember = "AnalytePK"

This works fine, but... I am trying to return the values of multiple selected items. It seems to only return the value of the first selected item in the group. Is it possible to do this by this method?

I have tried setting the SelectedIndex and it still only returns the value of the first item. any help would be appreciated.

[bgmacaw]

See SelectedIndexCollection

[bmahler]

That only returns the indexes that are selected, I need to get the value of each selected index. I came up with a way to do it, but it seems like a real work around and there must be a better way to accomplish this.

Dim intNucPk As Integer
 
        'A list to hold the indexes
        Dim ids As New List(Of Integer)
        'Add the selected indexes to the list
        For i As Integer = 0 To Me.lbNucs.SelectedIndices.Count - 1
            ids.Add(Me.lbNucs.SelectedIndices(i))
        Next
        'Set the selected Item to nothing
        lbNucs.SelectedItem = Nothing
 
        'Loop through the selected indicies
        For i As Integer = 0 To ids.Count - 1
            'Set the selected index
            lbNucs.SelectedIndex = ids.Item(i)
            'Get the value
            intNucPk = lbNucs.SelectedValue
            'Add the nuclide to the analysis code
            tryAddNuc(intNucPk)
            'Set the selected item to nothing
            lbNucs.SelectedItem = Nothing
        Next
        'Repopulate the listbox with the new values
        getNucsForAC()

[circuits2]

.SelectedItem should be a collection with a zero-based index. Did you try looping through .SelectedItem(index).Value?

[bgmacaw]

SelectedItems might be what you're looking for. It still requires a loop though

For Each SelectedItem As String In ListBox1.SelectedItems
    ListBox2.Items.Add(SelectedItem)
Next

Of course, the "As String" would need to be whatever object you were storing in the listbox.

It's too bad the following doesn't work

ListBox2.Items.AddRange(ListBox1.SelectedItems)

But for some reason the MS .NET Team decided to make ListBox.ObjectCollection and ListBox.SelectedObjectCollection incompatible.

[bmahler]

.SelectedItem(index).Value doe snot work. There is no value property for that.

@bgmacaw I guess you did not read my original post. I am looking to return the valuemember of each selected Item, not the index. The index is easy, but I need the ValueMember of that index. I have actually done this, by deselecting each item after it is added like so.

Dim intNucPk As Integer
 
        'A list to hold the indexes
        Dim ids As New List(Of Integer)
        'Add the selected indexes to the list
        For i As Integer = 0 To Me.lbNucs.SelectedIndices.Count - 1
            ids.Add(Me.lbNucs.SelectedIndices(i))
        Next
        'Loop through the selected indicies
        For i As Integer = 0 To ids.Count - 1
            intNucPk = lbNucs.SelectedValue
            'Add the nuclide to the analysis code
            tryAddNuc(intNucPk)
            'Deselect the item
            lbNucs.SetSelected(ids(i), False)
        Next
        'Repopulate the listbox with the new values
        getNucsForAC()

Seems like the only way to get the SelectedValue of the next item.

anyway, marking this thread resolved, because I found a solution.

[bgmacaw]

@bgmacaw I guess you did not read my original post. I am looking to return the valuemember of each selected Item, not the index. The index is easy, but I need the ValueMember of that index.

Sorry I missed that when I read your post. I didn't catch on that you meant ValueMember when you said value. I'm glad you resolved it.

Here's another way I found to do it:

For Each SelectedItem As DataRowView In ListBox1.SelectedItems
    ListBox2.Items.Add(SelectedItem("AnalytePK"))
Next

When you databind the control it puts a DataRowView object in the Listbox's Items collection so you can access any members of a row in the original DataTable that way.

[bmahler]

Thanks for that one, that is definitely more efficient than my method