one letter

[Sven1989]

if txtNaam.text = "O?:" & lstGekozenOpties.List(i) Then

the ? must represent one! letter. Must I use ? or * or something else ?

[Paul M]

wait what letter do you want ? to represent there is 26 :P

[Dnereb]

You need to use Like instead of Equals to(=)

if txtNaam.text Like "O?:" & lstGekozenOpties.List(i) Then

[Paul M]

You don't NEED TO the only problem here is that he hasn't stated everything

[Bruce Fox]

wait what letter do you want ? to represent there is 26 :P

Any of them.. he wants "?" to represent a wild card!

[Bruce Fox]

Here is one way (I have had a few...):

Option Explicit
 
Const ALPHABET As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
 
Private Sub Command1_Click()
    If Left$(txtNaam.Text, 1) = "O" And InStr(1, ALPHABET, Mid$(txtNaam.Text, 2, 1), vbTextCompare) And Mid$(txtNaam.Text, 3, 1) = ":" Then
        If Mid$(txtNaam.Text, 4, Len(txtNaam.Text) - 4) = lstGekozenOpties.List(i) Then
            'Do something
        End If
    End If
End Sub

[Bruce Fox]

Hmmm overkill - try this:

Use Like() to pattern match.

If UCase(txtNaan.Text) Like ("O[ABCDEFGHIJKLMNOPQRSTUVWXYZ]:" & UCase(lstGekozenOpties.List(i))) Then
        'Do stuff
    End If