[RESOLVED] Editing one line of a txt file?

[BrendanDavis]

Dim file As String
 
Open "C:\Test.txt" For Input As #1: file = Input(LOF(1), #1): Close #1
    file = Replace(file, "Selected car xxx", "Selected car " & Label1.Caption, 1, 1)
Open "C:\Test.txt" For Output As #1: Print #1, file: Close #1

That'll replace the first instance of "Selected car xxx" and no other, with "Selected car " & the label's caption.

If your string or file contains several instances of "Selected car xxx" before the one you wish to replace, you can simply do something like:

Dim file() As String, i As Integer, count As Integer: count = 0
 
Open "C:\Test.txt" For Input As #1: file = Split(Input(LOF(1), #1), vbCrLf): Close #1
 
For i = 0 To UBound(file)
    If InStr(file(i), "Selected car xxx") > 0 Then count = count + 1
    If count = 4 Then 'Find the fourth instance of the phrase
        newfile = newfile & Replace(file(i), "Selected car xxx", "Selected car " & _
        Label1.Caption) & vbNewLine
    Else
        newfile = newfile & file(i) & vbNewLine
    End If
Next
 
Open "C:\Test.txt" For Output As #1: Print #1, Mid(newfile, 1, Len(newfile) - 2): Close #1

In that example, it will find the 4th instance of "Selected car xxx" and replace only it with "Selected car " & Label1.Caption, and leave the other instances alone. Change the "4" in:

If count = 4 Then

...to whatever number instance you wish to find(26th, 62nd, whatever).

If all you need to do is replace something that will ALWAYS be on a certain line, then you could use one of the examples already provided by the other users here ;D