Simple linear algebra?

[INF3RN0666]

Hey guys,

I didn't know who to ask and I need an answer quickly :S. It should be simple, I just cant seem to remember how I did this problem.

What is the equation of the plane parallel to the vector (1, 1, -2) which passes through the points (1, 5, 18) and (4, 2, -6).

The answer is 5x - 3y + z = 8

How do I go about solving this?

Thanks for yout time!

[zaza]

You have two points in the plane, which means that you can work out a vector in the plane. And they have given you a second vector in the plane. Using these two you can work out the normal vector using the cross-product. Once you have that, you use n.r = n.m for a given point m in the plane to work out the equation, where n is the unit normal vector and r is the general equation (xi + yj + zk).

See this link for further details.

zaza