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Mar 13th, 2001, 10:04 PM
#1
Thread Starter
Dazed Member
yes i noticed your formula in a previous post but i wasnt too sure how to apply it....... woud this be correct?
Ax2 + Bx + C = 0 where A = 1, B = 5, C = 6
formula is ( -B + SquareRoot(B^2 - 4*A*C) ) / 2*A
so...... (-5 + sqr(5^2 - 4*1*6)) / 2 * 1
(-5 + sqr(25 - 24)) / 2 * 1
(-5 + sqr(1)) / 2 * 1
-6 /2*1 = -3
x = 3
would that be correct?
thanks bro....
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