yes i noticed your formula in a previous post but i wasnt too sure how to apply it....... woud this be correct?

Ax2 + Bx + C = 0 where A = 1, B = 5, C = 6

formula is ( -B + SquareRoot(B^2 - 4*A*C) ) / 2*A

so...... (-5 + sqr(5^2 - 4*1*6)) / 2 * 1

(-5 + sqr(25 - 24)) / 2 * 1

(-5 + sqr(1)) / 2 * 1

-6 /2*1 = -3

x = 3

would that be correct?
thanks bro....