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Sep 28th, 2006, 02:03 AM
#1
Thread Starter
New Member
Fibonacci Corrected
You all getting wrong the first terms of the series. The correct one is:
0, 1, 1, 2, 3, 5, 8, 13 ...
Hence, F(0)=0, F(1)=1
and F(n)=F(n-1)+F(n-2)
Joe Back
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Sep 28th, 2006, 02:41 PM
#2
Re: Fibonacci Corrected
Prove F(-N) = -F(N) when N is even.
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Oct 1st, 2006, 04:42 PM
#3
Member
Re: Fibonacci Corrected
Difficult really, since that is simply the definition of an even function. It's like saying prove dy/dx = lim delta(y)/delta(x) as delta tends towards 0. It's just the definition.
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Oct 1st, 2006, 06:36 PM
#4
Re: Fibonacci Corrected
!LKH's formula can be written as:
F(-n) = -(-1)nF(n)
Proof: For Fib series we know,
F(n) = F(n-1) + F(n-2)
So, F(n-2) = F(n) - F(n-1).
Therefore, Fib series, when extended to negative numbers become:
Code:
... -8, 5, -3, 2, -1, 1, 0, 1, 1, 2, 3, 5, 8, ...
When n is -1, answer is 1 (for n=1, ans=1), and when n = -2, answer is -1 (for n=2, ans=1) and so on.
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Oct 2nd, 2006, 11:39 AM
#5
Junior Member
Re: Fibonacci Corrected
 Originally Posted by Mattywoo2
Difficult really, since that is simply the definition of an even function. It's like saying prove dy/dx = lim delta(y)/delta(x) as delta tends towards 0. It's just the definition.
You're misunderstanding the question - the question stated you should prove the result when N is even, not when the function is even.
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