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Aug 19th, 2006, 02:49 PM
#1
Thread Starter
New Member
Linear programming problem
I got a LP problem that I'm stuck on.
A furniture factory makes tables and chairs. It takes 2 hours to assemble a table and 30 minutes to assemble a chair. Assembly is carried out by four people on the basis of one eight-hour shift per day. Customers buy at four chairs with each table which means that the factory has to make at most four times as many chairs as tables. The selling price is €135 per table and €50 per chair.
Formulate this as a linear programming problem to determine the daily production of tables and chairs which would maximise the total daily revenue to the factory and solve the problem using the simplex method.
My progress:
X1 = Amount of tables produced
X2 = Amount of chairs produced
Max Z = 135X1+50X2
Subject to:
120X1+30X2 ≤ 1920
4X1 ≥ X2
X1, X2 ≥ 0
Standard form:
Max Z = 135X1+50X2
Subject to:
4X1+X2+S1 = 64
4X1-X2-S2 = 0
X1, X2, S1, S2 ≥ 0
Are my constraints correct?
Thanks for your time.
Last edited by fobster; Aug 20th, 2006 at 04:45 AM.
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Aug 19th, 2006, 06:17 PM
#2
Addicted Member
Re: Linear programming problem
Yes, they are correct and the result must be 8 tables and 32 chairs selling for €2,680.
Try to reach these same conclusions yourself using the simplex method.
...este projecto dos Deuses que os homens teimam em arruinar...
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Aug 20th, 2006, 04:19 AM
#3
Addicted Member
Re: Linear programming problem
Actually there is a minor error
4X1+X2+S1 = 1920
should be either
120X1+30X2+S1 = 1920
or
4X1+X2+S1 = 64
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Aug 20th, 2006, 04:48 AM
#4
Thread Starter
New Member
Re: Linear programming problem
 Originally Posted by Glaysher
Actually there is a minor error
4X1+X2+S1 = 1920
should be either
120X1+30X2+S1 = 1920
or
4X1+X2+S1 = 64
Just a typo by me.
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Aug 20th, 2006, 04:54 AM
#5
Addicted Member
Re: Linear programming problem
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