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Jul 15th, 2006, 05:12 AM
#1
[RESOLVED] dice problem
There is a six faced die.Numbering should be done from 1 to 6.How many ways the numbering can be done , with a condition that 1 and 6, 2 and 5 , 3 and 4 comes on the opposite sides of the die.
is the answer 64??
Last edited by Harsh Gupta; Jul 15th, 2006 at 06:18 AM.
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Jul 15th, 2006, 11:35 AM
#2
Re: dice problem
There are only two ways this can be done.
1 (top)
2-3-5-4
6 (bottom)
or
1 (top)
2-4-5-3
6 (bottom)
Any other arrangement, given the restrictions, is a rotation of one of these.
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Jul 15th, 2006, 12:12 PM
#3
Re: dice problem
No the answer is 48. my previous calculation was wrong.
i will post the method later. busy right now!!
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Jul 15th, 2006, 12:36 PM
#4
Re: dice problem
There are 48 non-unique solutions. Of those, 24 can be represented by the first of my solutions, and the other 24 by the second.
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