confused about this code...

[benmartin101]

I read this in a tutorial and I'm wondering if someone could explain how this is true.

value_two     dw 0
value_three   dd 0

  mov   byte ptr [value_three + 1],"o"
  mov   word ptr [value_three + 2],2020h

here's the quote:

"mov byte ptr [value_two + 1],"l" : Same as above, except for the +1. The +1 means the assembler has to add one to the address of value_two. This way, an "l" is stored in the second byte of the word value_two (still get it?)

mov word ptr [value_three + 2],2020h : Word ptr means that we want to store a word. (this way the bytes will be stored in reverse order, see part 1) The +2 indicates that we want to store the value in the second word of the dword value_three."

I don't understand how "+2 indicates that we want to store the value in the second word of the dword value_three". Shouldn't it be stored in the location right after the dword value_three. Because if the quote is true, then the quote:
"mov byte ptr [value_two + 1],"l" : Same as above, except for the +1. The +1 means the assembler has to add one to the address of value_two. This way, an "l" is stored in the second byte of the word value_two (still get it?)"

would mean that +1 means the an "l" is stored in the "first"(not second) byte of the word value_two. Is +1 and +2 refering to bytes? or is +1 referring to a byte for each, since it is a byte pointer, and +2 referring to a word for each so its +2 words? I'm confused.

[chemicalNova]

The latter.

If memory servers that this:

is +1 referring to a byte for each, since it is a byte pointer, and +2 referring to a word for each so its +2 words?

...is correct.

chem