SelectionFormula Crystal Reports - Expert Wanted

[stewart_hafandeg]

Dear All

I was wondering whether anyone could help.

How come when I hard code in the selection formula it works fine but when I build the selection formula via a string it fails to launch the Crystal report window and work.

I have checked the string and it gives the EXACT syntax as the hard coding. Still it doesn't work.

I am at a loss as to why it doesn't work - Suggestions please.

Below is an example of my code. The string is built on the contents of a list box. Code is best viewed in 'Courier font' as I'm sure you'll already know.


Dim frmcount As Integer
Dim frmloop As Integer
Dim result As String

frmcount = List1.ListCount - 1

result = Chr(34) & "{query.lot_number}='"

For frmloop = 0 To frmcount
result = result & List1.List(frmloop) & "'"
If frmloop <> frmcount Then result = result & " or {query.lot_number}='"
Next frmloop

result = result & Chr(34)

RecallReport.SelectionFormula = result
RecallReport.PrintReport

Cheers


Stewart

[Anakim]

I believe the CHR(34) wrapping you have is unnecessary.

This works fine for me:

    Report.RecordSelectionFormula = "{tempreport.reportid}=" & miReportID

I fink you'd need to amend it slightly for a string

    Report.RecordSelectionFormula = "{tempreport.reportid}='" & msReportID & "'"

just add a single quote around the string to compare.

This may help, praps not..... I'm not a great fan of Crystal it has to be said, if I can delegate the report stuff then I usually do!

[stewart_hafandeg]

Because my criteria comes from a listbox then my selectionformula needs to be dynamic.

Therefore I cannot simply use.

RecallReport.SelectionFormula = "{query.lot_number}='" & ID & "'"

My string builds to include the ' or ' statement.

Example.

Listbox user selection = "A" and "B"

Then my SelectionFormula = "{query.lot_number}='A' or {query.lot_number}='B'"

If I hard code this in it works, but I can't because I cant restrict the user to a number of selections. I can build this SelectionFormula (string) via code (as I have done) so that it is exactly the same as the hard code but it fails to work.

I have to include the Chr(34) to make the string EXACTLY like the hard code.

I find it hard to understand why the hard code version works, but the string doesn't. Even though the syntax is EXACTLY the same.

Please help if you can.


Stewart