Invert percentages

[WorkHorse]

For some reason I'm having a brain freeze on this. I want to invert percentages. For example:

a = 1 : 17%
b = 2 : 33%
c = 3: 50%

Calculation is simply n/(a+b+c). But I want it inverted such that

a = 1 : 50%
b = 2 : 33%
c = 3: 17%

What's the formula I'm looking for?

[penagate]

Don't understand the question. How do you get a, b, c?

[Tom951]

You could do (4 - N) / (a + b + c)

N 4-N 4-N / (a+b+c)

1 3 50%
2 2 33%
3 1 17%


??

Tom

[gigemboy]

Put the objects in an array, then use Array.Reverse (or whatever Array.Reverse would be in VB6, if they have anything like that) ... of course, not sure why this is in the maths forum, unless I am missing something...

[fahad k]

This seems a bit vague but anyways,

a=100-b-a;
c=100-a-b;//new value of a.
b=100-c-a.//new value of c and a.